Profit Loss Percent on Multiple Items

Duration: 9 min

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Module outline

  1. About the Course: About the Course
  2. Paper-1 & 2 | Basic Numeracy: Ratio and Proportion (Ratios), Divisibility Rules, Mixture and Alligation, Permutation and Combination, Logarithm, Number System, HCF LCM, Sequence and Series (Series), Speed Time and Distance, Percentage, Average, Mensuration and Geometry, Age Problems, Arithmetic, Statistics, Probability, Profit and Loss, Simple Interest and Compound Interest, Partnership, Speed Mathematics and Basic Mathematics, Algebra, Powers and Exponents (Surds and Indices), Time and Work, Pipe and Cistern, RSSB Specific Videos - Basic Numeracy
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  4. Paper-1 & 2 | General Mental Ability: Mental Ability, RSSB Specific Videos - Mental Ability
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  24. Paper 1 - Full Mock Tests:
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  26. BCI Previous Year Papers:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This video is a tutorial on solving a profit and loss problem from an Infosys exam, presented by an instructor from Knowledge Gate. The core problem involves a man who buys 11 Surflexcel pouches for 10 rupees and sells 10 pouches for 11 rupees, and the task is to find the total profit or loss percentage. The instructor first demonstrates the 'traditional method' by calculating the cost price (CP) and selling price (SP) per pouch, then determining the total CP and SP for a common number of pouches (110) to find the overall profit percentage. He then introduces a 'short trick' method, which uses the formula: (a/b) * (c/d) - 1, where a is the number of items bought, b is the cost for those items, c is the number of items sold, and d is the selling price for those items. This trick directly yields the profit percentage. The video uses a digital whiteboard to write out the calculations and formulas, and the instructor explains each step clearly.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The video opens with a title card for a problem from an Infosys exam, asking to find the total profit or loss percentage for a transaction involving Surflexcel pouches. The instructor, Yash Jain Sir, introduces the problem: a man purchases 11 pouches for 10 rupees and sells 10 pouches for 11 rupees. He states that the question is from the Infosys exam (2010) and will be solved using a traditional method. The on-screen text clearly presents the problem statement and the instructor's name and channel, Knowledge Gate Educator.

  2. 2:00 – 5:00 02:00-05:00

    The instructor begins the 'traditional method' of solving the problem. He writes on a digital whiteboard, first calculating the cost price (CP) per pouch as 10/11 rupees and the selling price (SP) per pouch as 11/10 rupees. He then explains that to find the overall profit, he needs a common number of pouches. He calculates the total cost for 110 pouches (110 * 10/11 = 100 rupees) and the total selling price for 110 pouches (110 * 11/10 = 121 rupees). The profit is 121 - 100 = 21 rupees. The profit percentage is then calculated as (21/100) * 100 = 21%.

  3. 5:00 – 8:37 05:00-08:37

    The instructor introduces a 'short trick' to solve the problem in 2-3 seconds. He writes the formula: (a/b) * (c/d) - 1, where a=11 (pouches bought), b=10 (cost), c=10 (pouches sold), d=11 (selling price). He substitutes the values: (11/10) * (10/11) - 1 = 1 - 1 = 0. He then explains that this is incorrect and corrects the formula to (a/b) * (d/c) - 1, which gives (11/10) * (11/10) - 1 = 121/100 - 1 = 21/100 = 21%. He confirms the answer is 21% profit. The video ends with a 'Thanks for Watching' screen.

The video effectively teaches a common aptitude test problem by first presenting a detailed, step-by-step traditional method to build a solid understanding of the underlying concepts of cost price, selling price, and profit percentage. It then transitions to a more efficient 'short trick' method, demonstrating how to apply a formula to solve the same problem quickly. This progression from foundational understanding to a time-saving technique is a classic pedagogical approach for exam preparation, ensuring students can both understand the logic and apply a fast solution under time pressure.

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