Stack Practice questions

Duration: 5 min

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Inside: a video lesson and guided study material.

Module outline

  1. Paper 1 | Reasoning Test: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Data Sufficiency, Syllogisms, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Seating Arrangements, Blood Relations, Puzzle Solving (Puzzles), Venn Diagram, Analogy, Ranking, Order and Sequence, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Selection Decision Table (Decision Making), Logical Sequence Of Words, Cubes & Dices, Analytical Reasoning (Counting Figures Reasoning), Calendar, Alphabet and Word Tests, Numerical Reasoning, Number System, Averages, Mixtures and Alligation, Percentages, Series Completion, Analogy and Classification, Patterns in Two-Dimensional Figures, Coding and Decoding, Mathematical Operations, Direction Sense, Algebra, Logical Deduction and Induction, Syllogisms and Venn Diagrams, Critical Reasoning, Order, Ranking and Sequence, Reading Comprehension, Profit, Loss and Discount, Constraint Puzzles, Speed, Time and Distance, Traverse Surveying, Ratio and Proportion, Time and Work, Mensuration, Permutations and Combinations, Clocks and Calendars, Data Interpretation, Assembling and Grouping of Shapes, Transformation of Shapes, Three-Dimensional Patterns and Visualization, Cubes and Dice, Vocabulary, Blood Relations, Data Sufficiency
  2. Paper 1 | Numerical Analysis: Number System, HCF LCM, Percentage, Ratio and Proportion (Ratios), Average, Sequence and Series (Series), Powers and Exponents (Surds and Indices), Algebra, Statistics, Data Interpretation, Mental Ability, Arithmetic, Logarithm, Profit and Loss, Simple Interest and Compound Interest, Speed Time and Distance, Mixture and Alligation, Mensuration and Geometry, Permutation and Combination, Probability, Sequences and Series, Powers, Surds and Logarithms, Subject-Verb Agreement, Sentence Completion, Geometry, Sentence Structure and Correction, Data Sufficiency, Trigonometry, Measurement and Quantity Take-Off, Signal Space and Optimum Detection, Probability, Statistics, Algebra, Time and Work, Speed, Time and Distance, Data Interpretation, Graph Theory, Combinatorics
  3. Paper 1 | General Knowledge: State Wise GK, History, Geography, GK- Current Affairs, Static General Knowledge, Polity, Indian Economy
  4. Paper 1 | DBMS: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, SQL, Transaction Management, Concurrency Control, Relational Calculus, Database Security & Authorization, Database Recovery
  5. Paper 1 | Data Communication & Network: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Network Security, Security in Mobile and Wireless Computing, Input Output Organisation, File Management, Hardware Basics, Terms & Abbreviations, Protocols & Services, Network Access Technologies, Cyber Safety and Security, Basics of COA
  6. Paper 2 | System Analysis & Design: Fundamentals of Systems and Information Systems, SDLC and Development Approaches, Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Documentation and Software Requirements Specification (SRS), SDD and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management, Security, Risk Management & Maintenance, extras
  7. Paper 2 | Programming Language (Java): Java Fundamentals, OOPS with Java, Array, String, IO & References, Generic & Collections, Multithreading, Java, Miscellaneous, Control Flow, OOPS with C++, Stack, C Fundamentals, Arrays & Pointers, Object Oriented Technology, Control Flow & Looping, Introduction to Python
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

The video presents a C programming problem asking students to predict the output of a recursive function f(n) called with the argument 11. The instructor systematically traces the execution of the code, analyzing the base cases and recursive steps. He writes down the call tree on the whiteboard, breaking down f(11) into smaller sub-problems like f(5) and f(6). By evaluating each recursive call step-by-step, determining return values based on integer division and modulo operations, he calculates the final result. The process involves checking conditions like n <= 1 and n % 2 == 0 to decide the return path. The final output is determined to be 5, corresponding to option (D).

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The instructor introduces the problem "Predict the output of following program" and displays the C code on screen. He starts tracing the function f(11) written on the board. He evaluates the first condition if(n <= 1) as false for 11. Then he checks if(n%2 == 0), noting that 11 is odd, so this is also false. Consequently, he moves to the final return statement return f(n/2) + f(n/2+1), substituting 11 to get return f(5) + f(6). He begins expanding f(5) by writing Ret f(2) + f(3) underneath it, indicating the next level of recursion. He then analyzes f(2), checking 2 <= 1 (false) and 2%2 == 0 (true), leading to return f(1). He establishes that f(1) returns 1 because 1 <= 1 is true, writing f(2) = 1 on the side.

  2. 2:00 – 5:00 02:00-05:00

    Continuing the trace, the instructor evaluates f(3). Since 3 is odd, it hits the final return statement: return f(1) + f(2). Using the previously calculated values where f(1) = 1 and f(2) = 1, he determines f(3) = 2. He writes f(3) = 2 on the board. Returning to f(5), he sums the results of its children: f(2) + f(3) becomes 1 + 2, so f(5) = 3. Next, he analyzes f(6). Since 6 is even, the condition n%2 == 0 is true, so it returns f(6/2) which is f(3). Since f(3) is already known to be 2, f(6) = 2. Finally, he combines the results for the initial call: f(11) = f(5) + f(6) becomes 3 + 2, resulting in 5. He writes f(11) = 5 clearly on the board.

  3. 5:00 – 5:08 05:00-05:08

    The instructor concludes the problem by confirming the calculated result is 5. He points to option (D) 5 and places a checkmark next to it, indicating it is the correct answer. He briefly dismisses the other options, crossing out (A) Stack Overflow, (B) 3, and (C) 4 to show they are incorrect. The video ends with the final answer selected.

The lecture demonstrates a methodical approach to solving recursive function problems by manually tracing the call stack. The instructor breaks down complex calls into simpler sub-problems, utilizing a top-down expansion strategy. By calculating base cases first and working backwards up the recursion tree, he avoids stack overflow errors and correctly computes the final integer value. This step-by-step evaluation highlights the importance of understanding integer division and modulo operators in C recursion.

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