Using relational algebra, the query that finds customers, who have a balance…

PYQ RPSC Programmer 2013

Using relational algebra, the query that finds customers, who have a balance of over 3000 is

  1. A.

    πcustomer_name(σbalance>3000(Deposit))\pi_{\text{customer\_name}}(\sigma_{\text{balance}>3000}(\text{Deposit}))

  2. B.

    σcustomer_name(σbalance>3000(Deposit))\sigma_{\text{customer\_name}}(\sigma_{\text{balance}>3000}(\text{Deposit}))

  3. C.

    πcustomer_name(σbalance>3000(Borrow))\pi_{\text{customer\_name}}(\sigma_{\text{balance}>3000}(\text{Borrow}))

  4. D.

    σcustomer_name(πbalance>3000(Borrow))\sigma_{\text{customer\_name}}(\pi_{\text{balance}>3000}(\text{Borrow}))

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