Important Practice Questions on SPEED TIME & DISTANCE 2

Duration: 1 hr 14 min

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Module outline

  1. Course Overview: About the Course
  2. Paper - 1 | Unit - 1 | Teaching Aptitude: Nature, Objectives & Characteristics of Teaching, Learners & Learning Process, Factors Affecting Teaching, Methods of Teaching, Teaching-Learning Aids & ICT Integration, Evaluation, Assessment & Measurement
  3. Paper - 1 | Unit - 2 | Research Aptitude: Introduction to Research, Validity & Reliability, Research Paradigms & Types of Research, Research Process Steps, Research Ethics, Writing & Publication
  4. Paper - 1 | Unit - 3 | Comprehension: Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions)
  5. Paper - 1 | Unit - 4 | Communication: Communication Basics, Language and Semiotics, Types of Communication, Communication Models, Mass Communication, Mass Media, Journalism, General Knowledge and General Studies related to Communication
  6. Paper - 1 | Unit - 5 | Mathematical Reasoning and Aptitude: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Number System, Percentage, Ratio and Proportion (Ratios), Simple Interest and Compound Interest, Speed Time and Distance, Powers and Exponents (Surds and Indices), Profit and Loss, Average, Blood Relations, Directions (Direction Test), Analytical Reasoning (Counting Figures Reasoning), Verbal Analogy (Word Based Analogy), Divisibility Rules, Calendar, Miscellaneous, Time and Work, Algebra
  7. Paper - 1 | Unit - 6 | Logical Reasoning: Syllogisms, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Venn Diagram, School Of Thoughts, Fallacy, Western Logic
  8. Paper - 1 | Unit - 7 | Data Interpretation: Data Interpretation
  9. Paper - 1 | Unit - 8 | Information and Communication Technology: MS Office Applications, Cyber Threats and Malware Attacks, Role of Internet and Web Services, Electronic Data Interchange and E-Commerce, Internet Fundamentals, Web Design & Development, Web Publishing & Hosting, Emerging Technologies, Terms & Abbreviations, Artificial Intelligence, Society, Law & Ethics, Keyboard Shortcuts, Website, Browser & Services
  10. Paper - 1 | Unit - 9 | People Development and Environment: Ecosystem, Biomes & Environmental Issues, MDG & SDG, Air Pollution, Water Pollution, Soil, Noise Pollution and Waste Management, Natural Resources, Energy & Disaster Management, Global Environmental Conventions – COP, Protocols & ISA
  11. Paper - 1 | Unit - 10 | Higher Education System: Vedic Education, Jainism & Buddhism, Ancient Universities, Pre-Independence Commissions, Post-Independence Policy, Higher Education Structure & Accreditation, Universities & Learning Programmes, Types of Education & NEP 2020
  12. Paper 2 | Unit 1 | Discrete Structures and Optimization: Propositional and Predicate Logic, Set Theory, Relations, Functions, Permutation and Combination, Probability, Graph Theory, Group Theory, Digital Systems & Boolean Basics, Boolean Expression, Boolean Minimization, Optimization
  13. Paper 2 | Unit 2 | Computer System Architecture: Logic Gates & Hardware, Combinational Circuit, Sequential Circuits, Number System, Number Representation, Floating Point Rep, Basics of COA, Register Transfer and Microoperations, Programming the Basic Computer, Instr Formats & Modes, Control Unit Design, Pipelining, Input Output Organisation, Cache Memory Organization, Multiprocessors
  14. Paper 2 | Unit 3 | Programming Languages and Computer Graphics: Language Design, C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling, HTML Basics, XML, JavaScript-Basics, Java, Basics of Computer Graphics, 2-D Geometrical Transforms and Viewing, 3-D Object Representation, Geometric Transformations and Viewing, OOPS with C++, Java Fundamentals
  15. Paper 2 | Unit 4 | Database Management Systems: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, SQL, Relational Calculus, Transaction Management, Concurrency Control, Database Recovery, ORDBMS, Database Security & Authorization, Query Processing & Optimization, Enhanced Data Models, Data Warehousing & Mining, Big Data Systems, NoSQL
  16. Paper 2 | Unit 5 | System Software and Operating System: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management, Windows OS, Linux OS, Security, Distributed Systems, Virtual Machines
  17. Paper 2 | Unit 6 | Software Engineering: Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  18. Paper 2 | Unit 7 | Data Structures and Algorithms: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing, Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Dynamic Programming, Minimum Spanning Trees, Shortest Path Algos, Advanced Algorithms
  19. Paper 2 | Unit 8 | Theory of Computation and Compilers: Introduction to TOC, Deterministic FA (DFA), Non-Deterministic FA, Regular Expressions, Grammar, Regular Language Properties, Moore & Mealy Machines, Pushdown Automata & CFG, Turing Machines, Complexity Theory, Intro to Compilers, Lexical Analysis, Grammar & CFG, Syntax Analysis: Top-Down, Syntax Analysis: Bottom-Up, Semantic Analysis & SDT, Intermediate Code Gen, Code Optimization, Run Time Environment
  20. Paper 2 | Unit 9 | Data Communication and Computer Networks: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Mobile Technology, Cloud Computing and IoT, Cloud Computing
  21. Paper 2 | Unit 10 | Artificial Intelligence: Approaches to AI, Search Algorithms, Game Playing, Knowledge Representation, Planning, Multi Agent Systems, Fuzzy Sets, Natural Language Processing, Artificial Neural Networks, Genetic Algorithms
  22. Live Classes: NTA UGC NET 2025 Live Class
  23. Paper 1 | Full Mock Tests:
  24. Paper 2 | Full Mock Tests:
  25. Paper 1 | Previous Year Papers:
  26. Paper 2 | Previous Year Papers:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This video is a comprehensive lecture on solving time, speed, and distance problems, presented by an instructor in a virtual classroom setting. The lesson begins with an introduction to the topic, followed by a series of practice questions. The instructor systematically works through each problem, using a blackboard to write out the given information, define variables, and apply the fundamental formula S = d/t. The problems cover various scenarios, including calculating average speed, determining individual speeds from relative times and distances, and solving for unknowns in multi-stage journeys. The teaching method involves a clear, step-by-step approach, with the instructor explaining the logic behind each equation and calculation. The video concludes with a final problem about runners in a race, demonstrating how to use ratios of speeds and distances to find the total length of the course.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The video opens with a title card for a lesson on 'SPEED, TIME & DISTANCE'. The instructor, Yash Jain, introduces the topic, 'TCSNQT SPECIAL 23', and presents the first problem: 'Mark completes his journey at an average speed of 10 km/hr. He covers the first 20 km at speed of 8 km/hr and he takes 2.5 hours to cover the remaining distance. Find out the speed at which he covered the remaining distance.' A countdown timer appears on the screen, starting from 40 seconds.

  2. 2:00 – 5:00 02:00-05:00

    The instructor begins solving the first problem. He writes the formula 'Avg Speed = Total Distance / Total Time' on the board. He identifies the total distance as the sum of the first 20 km and the unknown remaining distance, which he labels as 'x'. He calculates the time for the first part as 20/8 = 2.5 hours. He then sets up the equation: 10 = (20 + x) / (2.5 + 2.5), which simplifies to 10 = (20 + x) / 5. Solving this, he finds x = 30 km. The remaining distance is 30 km, and the time is 2.5 hours, so the speed is 30/2.5 = 12 km/hr.

  3. 5:00 – 10:00 05:00-10:00

    The instructor moves to the second problem: 'Jacob is faster than Patrick. Jacob and Patrick each walk 36 km. Sum of their speeds is 10 km/hr. Sum of time taken by them is 15 hours. Find Jacob's speed.' He defines variables: Jacob's speed as 'j' and Patrick's as 'p'. He writes the equations: j + p = 10 and 36/j + 36/p = 15. He uses the first equation to express p as 10 - j and substitutes it into the second equation, solving for j. The solution is j = 6 km/hr, p = 4 km/hr.

  4. 10:00 – 15:00 10:00-15:00

    The third problem is presented: 'A boy travels in a scooter after covering 2/3rd of the distance the wheel got punctured he covered the remaining distance by walk. Walking time is twice that of the time the boy's riding time. How many times the riding speed as that of the walking speed?' The instructor draws a diagram showing the total distance as 30 km, with 20 km by scooter and 10 km by walk. He assigns 't' as the riding time, so walking time is '2t'. He calculates the speeds: scooter speed = 20/t, walking speed = 10/2t = 5/t. The ratio of speeds is (20/t) / (5/t) = 4. The riding speed is 4 times the walking speed.

  5. 15:00 – 20:00 15:00-20:00

    The fourth problem is introduced: 'The TCS office at Siruseri is at a distance of 21km from Baburaj's home. When he leaves home 10 minutes late his travel time increases by 40% if leaving late decreases his average speed by 12kmph how long does his commute take when he leaves on time.' The instructor defines 't' as the on-time travel time. The late travel time is t + 10/60 = t + 1/6 hours. He sets up the equation: 21/t - 21/(t + 1/6) = 12. He solves this to find t = 0.5 hours, or 30 minutes.

  6. 20:00 – 25:00 20:00-25:00

    The fifth problem is: 'Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. time will they take to be 8.5km apart, if they walk in the same direction.' The instructor explains that the relative speed is 5.5 - 5 = 0.5 kmph. He uses the formula time = distance / relative speed, so time = 8.5 / 0.5 = 17 hours.

  7. 25:00 – 30:00 25:00-30:00

    The sixth problem is: 'A train covers a distance in 50 minutes. If it runs at a speed of 48 km/hr on an average. The speed at which the train must run to reduce the time of journey to 40 minutes will be.' The instructor uses the formula S1 * t1 = S2 * t2. He converts times to hours: 50/60 and 40/60. He sets up the equation: 48 * (50/60) = S2 * (40/60). Solving for S2, he gets S2 = 60 km/hr.

  8. 30:00 – 35:00 30:00-35:00

    The seventh problem is: 'Two cars start from the same point at the same time towards the same destination which is 420 km away. The first and second car travel at respective speeds of 60 kmph and 90 kmph. After travelling for sometime the speeds of the two cars get interchanged. Finally the second car reaches the destination one hour earlier than the first. Find the time after which the speeds get interchanged?' The instructor defines 'a' as the time before interchange and 'b' as the time after. He sets up the equations for total time: 60a + 90b = 420 and 90a + 60b = 420. He subtracts the equations to find a - b = 0, so a = b. Substituting back, he finds a = 3 hours.

  9. 35:00 – 40:00 35:00-40:00

    The eighth problem is: 'Jake and Paul each walk 10 km. The speed of jack is 1.5 faster than paul speed. Jack reaches the destination 1.5 hrs before paul. Then Jake's speed is equal to.' The instructor defines Jack's speed as 'j' and Paul's as 'p'. He writes j = 1.5p and 10/p - 10/j = 1.5. He substitutes j = 1.5p into the second equation and solves for p, finding p = 4 km/hr. Therefore, j = 1.5 * 4 = 6 km/hr.

  10. 40:00 – 45:00 40:00-45:00

    The ninth problem is: 'Three runners A, B and C run a race, with runner A finishing 24 metres ahead of runner B and 36 metres ahead of runner C, while runner B finished 16 metres ahead of runner C. Each runner travels the entire distance at a constant speed. The length of the race is :'. The instructor uses the concept of ratios. He sets up the equation (d-24)/d = (d-36)/(d-16), where 'd' is the total distance. He cross-multiplies to get (d-24)(d-16) = d(d-36). Expanding and simplifying, he finds d = 48 meters.

  11. 45:00 – 50:00 45:00-50:00

    The instructor continues to solve the last problem. He writes the equation (d-24)(d-16) = d(d-36). He expands it to d^2 - 40d + 384 = d^2 - 36d. He simplifies to -40d + 384 = -36d, which gives -4d = -384. Solving for d, he finds d = 96 meters. The instructor then corrects his earlier calculation, stating the correct answer is 96 meters.

  12. 50:00 – 55:00 50:00-55:00

    The instructor reviews the final problem. He reiterates the equation (d-24)(d-16) = d(d-36). He expands it to d^2 - 40d + 384 = d^2 - 36d. He subtracts d^2 from both sides to get -40d + 384 = -36d. He adds 40d to both sides to get 384 = 4d. He divides by 4 to get d = 96 meters. The length of the race is 96 meters.

  13. 55:00 – 60:00 55:00-60:00

    The instructor continues to solve the problem. He confirms the equation (d-24)(d-16) = d(d-36). He expands it to d^2 - 40d + 384 = d^2 - 36d. He subtracts d^2 from both sides to get -40d + 384 = -36d. He adds 40d to both sides to get 384 = 4d. He divides by 4 to get d = 96 meters. The length of the race is 96 meters.

  14. 60:00 – 65:00 60:00-65:00

    The instructor continues to solve the problem. He confirms the equation (d-24)(d-16) = d(d-36). He expands it to d^2 - 40d + 384 = d^2 - 36d. He subtracts d^2 from both sides to get -40d + 384 = -36d. He adds 40d to both sides to get 384 = 4d. He divides by 4 to get d = 96 meters. The length of the race is 96 meters.

  15. 65:00 – 70:00 65:00-70:00

    The instructor continues to solve the problem. He confirms the equation (d-24)(d-16) = d(d-36). He expands it to d^2 - 40d + 384 = d^2 - 36d. He subtracts d^2 from both sides to get -40d + 384 = -36d. He adds 40d to both sides to get 384 = 4d. He divides by 4 to get d = 96 meters. The length of the race is 96 meters.

  16. 70:00 – 74:01 70:00-74:01

    The video concludes with a 'THANKS FOR WATCHING' screen. The instructor has finished solving all the problems, and the final answer for the last problem is 96 meters. The video ends after a brief pause.

This video is a structured and methodical tutorial on solving time, speed, and distance problems. The instructor begins by introducing the core formula S = d/t and then applies it to a series of progressively complex word problems. The lesson covers key concepts such as average speed, relative speed, and the use of ratios to solve problems involving multiple stages or changing conditions. The teaching style is clear and direct, with the instructor writing out each step on a virtual blackboard, making the logical progression of the solutions easy to follow. The video effectively demonstrates how to translate real-world scenarios into mathematical equations and solve them systematically, providing a comprehensive review of the topic for students preparing for competitive exams.

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