Suppose transmission rate of a channel is 32 kbps. If there are ‘8’ routes…
2016
Suppose transmission rate of a channel is 32 kbps. If there are ‘8’ routes from source to destination and each packet p contains 8000 bits. Total end to end delay in sending packet P is _____.
- A.
2 sec
- B.
3 sec
- C.
4 sec
- D.
1 sec
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Show answer & explanation
Correct answer: A
Key idea: total end-to-end transmission delay = (packet size ÷ transmission rate) × number of sequential links.
Compute transmission time per link: 8000 bits ÷ 32000 bits/s = 0.25 s.
Multiply by number of sequential links (8): 0.25 s × 8 = 2 s.
Answer: 2 sec.
Note: This calculation assumes the phrase '8 routes' means the packet traverses 8 sequential links (hops). It also assumes only transmission delay is considered and ignores propagation, processing, and queuing delays.