Cut and General cuboid rule

Duration: 8 min

This video lesson is available to enrolled students.

Return to /learn/LTI-MINDTREE-PREPARATION/quantitative-ability/mensuration-and-geometry/3d-mensuration-solid-figures/asset-cut-and-general-cuboid-rule after enrolling

Inside: a video lesson and guided study material.

Module outline

  1. English Comprehension/Verbal Ability: Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Vocabulary, Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Subject Verb Agreement (Verb Noun Agreement), Tenses, Verb, Articles, Preposition, Conjunction, Pronoun, Noun, Adjectives, Adverb, Modals, Cloze Test (Cloze Passage), Active Passive Voice (Voice), Direct and Indirect Speech, Sentence Construction
  2. Logical Ability: Coding Decoding, Directions (Direction Test), Analogy, Inequality, Data Sufficiency, Series (Number and Letter Series) (Numerical Relations and Reasoning), Syllogisms, Seating Arrangements, Puzzle Solving (Puzzles), Blood Relations, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Ranking, Order and Sequence, Logical Sequence Of Words, Data Arrangement, Venn Diagram, Calendar, Clock
  3. Quantitative Ability: Logarithm, Permutation and Combination, Probability, Profit and Loss, Speed Time and Distance, Mixture and Alligation, Partnership, Simple Interest and Compound Interest, Percentage, Ratio and Proportion (Ratios), Average, Time and Work, Pipe and Cistern, Number System, Divisibility Rules, HCF LCM, Algebra, Powers and Exponents (Surds and Indices), Mensuration and Geometry, Age Problems, Data Interpretation, Sequence and Series (Series)
  4. Basic Analytical Ability: Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Analytical Reasoning (Counting Figures Reasoning), Cubes & Dices, Selection Decision Table (Decision Making)
  5. Computer Programming: Pseudo Codes, Coding Questions by Yash Sir, C Programming by Yash Sir, Programming in C++, Java, Python for Placements by Yash Sir
  6. DBMS (Computer Science): Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Transaction Management, Concurrency Control, Database Security & Authorization
  7. SQL (Computer Science): SQL
  8. OS (Computer Science): Introduction to OS, Process Management, CPU Scheduling, Deadlock, Process Synchronization, Threads & Process Creation, Memory Management, Virtual Memory, File Management
  9. Computer Networks (Computer Science): Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security
  10. Data Structures (Computer Science): Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  11. OOPs (Computer Science): Object Oriented Programming (OOPS)
  12. Software Engineering (Computer Science): Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  13. SVAR Conversational - Spoken English: Communication Assessment
  14. HR Interview: MR & HR Interview Preparation
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This lecture covers two main geometry topics: the cut and general cuboid rule, and calculating the longest diagonal of a cuboid. The first section explains that cutting a cube or cuboid into smaller pieces increases the number of pieces and surface area but does not change the total volume. Formulas are provided for calculating the side length of small cubes (a/n), the number of pieces (n^3 or pqr for a cuboid), and the cuts required without stacking (3(n-1) for a cube or (p-1)+(q-1)+(r-1) for a cuboid). The instructor uses visual grids and handwritten annotations to illustrate these concepts. The second section transitions to finding the longest diagonal of a cuboid using the formula d = √(a² + b² + h²). A worked example with dimensions 1.2 cm × 1.3 cm × 1.5 cm is solved, yielding an answer of approximately 2.23 cm from the given options (2.22, 2.32, 2.23, 2.35 cm). The final section briefly introduces a problem on cube surface area to diagonal, where a surface area of 13.5 m² is used with the formula S = 6a² to find a² = 2.25 and a = 1.5 m.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The instructor introduces the concept that cutting a cube or cuboid into smaller pieces increases the number of pieces and surface area but does not change total volume. On-screen text displays key formulas: 'Side of each small cube = a/n', 'Number of small cubes = n^3', and 'Cuts required without stacking = 3(n - 1)'. The instructor draws a red grid on the screen to visually represent dividing a cube's faces, writing '1' inside one square. The general cuboid rule is introduced with text showing 'Number of pieces = pqr' and 'Cuts required without rearranging or stacking = (p - 1) + (q - 1) + (r - 1)'. The instructor circles 'a/n' and writes 'a/3' below it, suggesting a specific example where n=3.

  2. 2:00 – 5:00 02:00-05:00

    The lecture continues with the general cuboid rule, emphasizing that cutting does not change total volume. The instructor highlights formulas for side length, number of small cubes, and cuts required, drawing red circles around key terms like 'n', 'n^3', and 'a^3'. The slide then transitions to a new topic: finding the longest diagonal of a cuboid. A problem is presented with dimensions '1.2 cm × 1.3 cm × 1.5 cm' and four options listed (2.22, 2.32, 2.23, 2.35 cm). A wireframe cuboid with a red diagonal arrow is shown at the bottom left. The instructor writes 'd = √' in red handwriting, completing it as 'd = √(a² + b² + h²)' and substituting the values '1.2² + 1.5² + 1.3²'.

  3. 5:00 – 7:34 05:00-07:34

    The instructor completes the longest diagonal calculation, showing 'd = √1.49' with a note and a circled value under the radical sign, arriving at an answer of 2.23 cm from the options. The slide then switches to a new topic titled 'Cube Surface Area to Diagonal', stating the surface area is '13.5 m²'. A red-boxed formula 'S = 6a²' is displayed, with step-by-step work computing 'a² = 13.5/6 = 2.25' and a circled value of '1.5'. This section demonstrates how to find the side length from surface area, which can then be used to calculate the diagonal of a cube.

The lecture progresses from theoretical rules about cutting cuboids to practical applications involving diagonals and surface area. The first part establishes foundational formulas for pieces and cuts, using visual aids like grids to make abstract concepts concrete. The transition to diagonal calculation shows how these geometric principles apply to real problems, with a clear worked example demonstrating the formula d = √(a² + b² + h²). The final section on surface area to diagonal extends the learning by showing how one property (surface area) can be used to find another (side length, and subsequently diagonal). The teaching style combines on-screen text formulas with handwritten annotations, creating a layered explanation that reinforces key concepts through multiple representations. The use of specific numerical examples helps students see how the general rules apply to concrete problems.

Loading lesson…