Tree Practice Question

Duration: 2 min

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Inside: a video lesson and guided study material.

Module outline

  1. English Comprehension/Verbal Ability: Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Vocabulary, Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Subject Verb Agreement (Verb Noun Agreement), Tenses, Verb, Articles, Preposition, Conjunction, Pronoun, Noun, Adjectives, Adverb, Modals, Cloze Test (Cloze Passage), Active Passive Voice (Voice), Direct and Indirect Speech, Sentence Construction
  2. Logical Ability: Coding Decoding, Directions (Direction Test), Analogy, Inequality, Data Sufficiency, Series (Number and Letter Series) (Numerical Relations and Reasoning), Syllogisms, Seating Arrangements, Puzzle Solving (Puzzles), Blood Relations, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Ranking, Order and Sequence, Logical Sequence Of Words, Data Arrangement, Venn Diagram, Calendar, Clock
  3. Quantitative Ability: Logarithm, Permutation and Combination, Probability, Profit and Loss, Speed Time and Distance, Mixture and Alligation, Partnership, Simple Interest and Compound Interest, Percentage, Ratio and Proportion (Ratios), Average, Time and Work, Pipe and Cistern, Number System, Divisibility Rules, HCF LCM, Algebra, Powers and Exponents (Surds and Indices), Mensuration and Geometry, Age Problems, Data Interpretation, Sequence and Series (Series)
  4. Basic Analytical Ability: Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Analytical Reasoning (Counting Figures Reasoning), Cubes & Dices, Selection Decision Table (Decision Making)
  5. Computer Programming: Pseudo Codes, Coding Questions by Yash Sir, C Programming by Yash Sir, Programming in C++, Java, Python for Placements by Yash Sir
  6. DBMS (Computer Science): Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Transaction Management, Concurrency Control, Database Security & Authorization
  7. SQL (Computer Science): SQL
  8. OS (Computer Science): Introduction to OS, Process Management, CPU Scheduling, Deadlock, Process Synchronization, Threads & Process Creation, Memory Management, Virtual Memory, File Management
  9. Computer Networks (Computer Science): Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security
  10. Data Structures (Computer Science): Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  11. OOPs (Computer Science): Object Oriented Programming (OOPS)
  12. Software Engineering (Computer Science): Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  13. SVAR Conversational - Spoken English: Communication Assessment
  14. HR Interview: MR & HR Interview Preparation
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

The video features an educational lecture by Sanchit Jain Sir from Knowledge Gate, focusing on a C programming problem involving binary trees. The specific task is to complete a function named `maxDepth` which calculates the maximum depth or height of a binary tree, noting that the root is at level 1. The code snippet provided on screen defines the function signature `int maxDepth(struct node* node)`. The instructor walks through the logic, starting with the base case: `if (node == NULL) return 0;`. This condition ensures that if a node does not exist, the depth contribution is zero. Following the base case, the `else` block handles the recursive step. The code calculates the depth of the left subtree using `int lDepth = maxDepth(node->left);` and the right subtree using `int rDepth = maxDepth(node->right);`. The critical part of the lecture is analyzing the final return statements. The code presents a conditional check: `if (lDepth > rDepth) return X; else return Y;`. The instructor explains that to find the total height, one must take the larger of the two subtree depths and add 1 to account for the current node itself. Consequently, the placeholders X and Y must represent the depth of the respective subtrees incremented by one. The question text at the bottom asks: "What should be the values of X and Y so that the function works correctly?". The visible options are (A) X = lDepth, Y = rDepth; (B) X = lDepth + 1, Y = rDepth + 1; (C) X = lDepth - 1, Y = rDepth - 1; and (D) None of the above. The instructor emphasizes that since the depth includes the current node, the value returned must be the subtree depth plus one. He points to the code structure to justify why adding 1 is necessary for the correct calculation of tree height, highlighting the recursive definition where height is 1 + max(left_height, right_height). The watermark "KNOWLEDGEGATE" is visible throughout the screen. The instructor is seated in a black gaming chair, wearing a white t-shirt with the Knowledge Gate logo.

Chapters

  1. 0:00 – 1:39 00:00-01:39

    The video analyzes a C function `maxDepth` for binary trees. It covers the base case `if (node==NULL) return 0;`, the recursive calculation of `lDepth` and `rDepth`, and the logic to determine the return values X and Y, which must account for the current node's level by adding 1 to the subtree depths. The instructor explains that the height of a node is 1 plus the maximum height of its children, requiring the addition of 1 in the return statement.

The lecture reinforces the recursive definition of tree height, where the height of a node is 1 plus the maximum height of its children, requiring the addition of 1 in the return statement to correctly calculate the total depth.

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