Practice Question

Duration: 3 min

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Inside: a video lesson and guided study material.

Module outline

  1. English Comprehension/Verbal Ability: Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Vocabulary, Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Subject Verb Agreement (Verb Noun Agreement), Tenses, Verb, Articles, Preposition, Conjunction, Pronoun, Noun, Adjectives, Adverb, Modals, Cloze Test (Cloze Passage), Active Passive Voice (Voice), Direct and Indirect Speech, Sentence Construction
  2. Logical Ability: Coding Decoding, Directions (Direction Test), Analogy, Inequality, Data Sufficiency, Series (Number and Letter Series) (Numerical Relations and Reasoning), Syllogisms, Seating Arrangements, Puzzle Solving (Puzzles), Blood Relations, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Ranking, Order and Sequence, Logical Sequence Of Words, Data Arrangement, Venn Diagram, Calendar, Clock
  3. Quantitative Ability: Logarithm, Permutation and Combination, Probability, Profit and Loss, Speed Time and Distance, Mixture and Alligation, Partnership, Simple Interest and Compound Interest, Percentage, Ratio and Proportion (Ratios), Average, Time and Work, Pipe and Cistern, Number System, Divisibility Rules, HCF LCM, Algebra, Powers and Exponents (Surds and Indices), Mensuration and Geometry, Age Problems, Data Interpretation, Sequence and Series (Series)
  4. Basic Analytical Ability: Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Analytical Reasoning (Counting Figures Reasoning), Cubes & Dices, Selection Decision Table (Decision Making)
  5. Computer Programming: Pseudo Codes, Coding Questions by Yash Sir, C Programming by Yash Sir, Programming in C++, Java, Python for Placements by Yash Sir
  6. DBMS (Computer Science): Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Transaction Management, Concurrency Control, Database Security & Authorization
  7. SQL (Computer Science): SQL
  8. OS (Computer Science): Introduction to OS, Process Management, CPU Scheduling, Deadlock, Process Synchronization, Threads & Process Creation, Memory Management, Virtual Memory, File Management
  9. Computer Networks (Computer Science): Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security
  10. Data Structures (Computer Science): Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  11. OOPs (Computer Science): Object Oriented Programming (OOPS)
  12. Software Engineering (Computer Science): Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  13. SVAR Conversational - Spoken English: Communication Assessment
  14. HR Interview: MR & HR Interview Preparation
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This educational video demonstrates how to calculate the memory address of a specific element within a two-dimensional array using the Row Major Order storage scheme. The instructor presents a specific problem where the array A has non-standard indexing ranges: rows from 5 to 15 and columns from -8 to 8. The total dimensions are given as A[11][17]. The problem asks for the address of element A[8][5]. Essential parameters are provided: a Base Address of 800 and an element size of 4 memory cells. The lecture walks through the derivation of the address calculation formula and applies it to solve the numerical problem, highlighting the handling of negative lower bounds.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The session begins with the problem statement displayed on screen: Q A[5.....15, -8.....8] is A[11][17] and we are supposed to find A[8][5]. The instructor identifies the given values: Row Major Order, Base Address = 800, and element size w = 4. He writes the general formula for Row Major Order on the board: A[i, j] = B + w * [(i - li) (ul - ll + 1) + (j - lj)]. He explicitly defines the lower and upper limits for rows (li=5, ui=15) and columns (lj=-8, uj=8). He notes that the term (ul - ll + 1) represents the total number of columns, which is 17. He sets up the substitution for the target element A[8][5], identifying i=8 and j=5.

  2. 2:00 – 3:14 02:00-03:14

    The instructor performs the arithmetic substitution. He writes 800 + 4 * [(8 - 5) * 17 + (5 - (-8))]. He calculates the row difference (8 - 5) as 3. He calculates the column difference (5 - (-8)) as 13. He multiplies the row difference by the column count: 3 * 17 = 51. He adds the column difference to this product: 51 + 13 = 64. This sum represents the total number of elements skipped. He multiplies this by the element size: 4 * 64 = 256. Finally, he adds this offset to the base address: 800 + 256, resulting in the final address 1056.

The video provides a clear, step-by-step guide to memory address calculation for 2D arrays. It emphasizes the formula's structure, particularly how the row index is weighted by the total column count. The example with negative lower bounds serves as a practical test of understanding the (index - lower_limit) component of the formula. The final calculation confirms the address is 1056, reinforcing the method for handling non-zero-based indexing in programming and data structures.

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