What is the size of the physical address space in a paging system which has a…
2014
What is the size of the physical address space in a paging system which has a page table containing 64 entries of 11 bit each (including valid and invalid bit) and a page size of 512 bytes?
- A.
211
- B.
215
- C.
219
- D.
220
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Correct answer: C
First, determine the number of bits used for the frame number. Each page table entry is 11 bits, including one valid/invalid bit, so there are 10 bits for the frame number. This means there can be 2^10 frames in physical memory.
Second, convert the page size to a power of 2: 512 bytes is 2^9 bytes. Finally, calculate the total physical address space by multiplying the number of frames by the page size: 2^10 × 2^9 = 2^19 bytes.