If the mean of a normal frequency distribution of 1000 items is 25 and its…
2009
If the mean of a normal frequency distribution of 1000 items is 25 and its standard deviation is 2.5, then its maximum ordinate is
- A.
(1000/√2π).e-25
- B.
1000/√2π
- C.
(1000/√2π ).e-2.5
- D.
400/√2π
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Correct answer: D
The maximum ordinate of a normal frequency distribution is determined by the formula y_max = N / (sigma * sqrt(2pi)). Given N=1000 and sigma=2.5, substituting these values yields 1000 / (2.5 * sqrt(2pi)), which simplifies mathematically to 400 / sqrt(2pi).