In a class B subnet, we know the IP address of one host and the mask as given…

The subnet mask 255.255.224.0 corresponds to a /19 prefix, affecting the third octet with a block size of 32 (calculated as 256 - 224). For the given IP address 125.134.112.66, we examine the third octet value of 112. Dividing 112 by the block size of 32 yields a quotient of 3, placing it in the subnet starting at 96 (3 * 32). Therefore, the network address is determined to be 125.134.96.0.