What will be the efficiency of a Stop and Wait protocol, if the transmission…
2013
What will be the efficiency of a Stop and Wait protocol, if the transmission time for a frame is 20ns and the propagation time is 30ns?
- A.
20%
- B.
25%
- C.
40%
- D.
66%
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Correct answer: B
The efficiency of the Stop and Wait protocol is calculated using the formula eta = Tt / (Tt + 2Tp). Given a transmission time of 20ns and propagation time of 30ns, the total cycle time is 20 + 2(30) = 80ns. Dividing the transmission time by the total cycle time yields 20/80 = 0.25 or 25%.