Finding ratio of 2 numbers from their sum & difference

Duration: 3 min

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Module outline

  1. About Course: About the Course
  2. Paper 1 | Quantitative Aptitude: Speed Mathematics and Basic Mathematics, Percentage, Ratio and Proportion (Ratios), Powers and Exponents (Surds and Indices), Logarithm, Sequence and Series (Series), Mensuration and Geometry, Data Interpretation, Average, Arithmetic
  3. Paper 1 | Logical Reasoning: Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Series (Number and Letter Series) (Numerical Relations and Reasoning), Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Analogy, Cubes & Dices, Syllogisms
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  5. Paper 1 | Unit Tests:
  6. Paper 1 | Full-Length Mock Tests:
  7. Paper 2 | Engineering Mathematics: Set Theory, Relations, Functions, Graph Theory, Group Theory, Propositional and Predicate Logic, Linear Algebra, Calculus, Permutation and Combination, Probability, Statistics
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  11. Paper 2 | Algorithms: Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Dynamic Programming, Minimum Spanning Trees, Shortest Path Algos
  12. Paper 2 | Theory Of Computation/Automata Theory: Introduction to TOC, Deterministic FA (DFA), Non-Deterministic FA, Regular Expressions, Grammar, Regular Language Properties, Moore & Mealy Machines, Pushdown Automata & CFG, Turing Machines, Complexity Theory
  13. Paper 2 | Compiler Design: Intro to Compilers, Lexical Analysis, Grammar & CFG, Syntax Analysis: Top-Down, Syntax Analysis: Bottom-Up, Semantic Analysis & SDT, Intermediate Code Gen, Code Optimization, Run Time Environment
  14. Paper 2 | Operating System: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management
  15. Paper 2 | DataBase Management System/DBMS: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, SQL, Relational Calculus, Transaction Management, Concurrency Control, Database Recovery
  16. Paper 2 | Computer Networks: Introduction to CN, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware Basics
  17. Paper 2 | CS/IT Sectional Mock Tests:
  18. Complete Paper Full Mock Test:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This short math lesson teaches how to find the ratio of two numbers when given the ratio of their sum and difference. The instructor introduces variables a and b, sets up (a+b)/(a-b) = given ratio, then solves the example where sum:diff = 9:2. Cross-multiplication gives 2(a+b) = 9(a-b), leading to 11b = 7a and a/b = 11/7. A shortcut formula a/b = (9+2)/(9-2) confirms the result 11:7. The video ends with a thanks screen.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The lesson opens with the title 'Finding Ratio of Numbers Given Ratio of Sum & Difference'. The instructor defines two numbers as a and b, writes 'a, b = x ?', and establishes the core relationship (a+b)/(a-b) = given ratio, with a circled 'a/b' indicating the target. The example question appears: 'Ratio of sum & difference of two numbers is 9 : 2. Find the ratio of numbers.' The instructor writes 'Sum/Diff = 9/2' and begins forming the equation (a+b)/(a-b) = 9/2, setting up the algebraic method.

  2. 2:00 – 3:11 02:00-03:11

    The instructor solves the equation by cross-multiplying: 2(a+b) = 9(a-b). Expanding and simplifying yields 11b = 7a, so a/b = 11/7. A shortcut formula is then shown: a/b = (9+2)/(9-2) = 11/7, confirming the ratio of numbers is 11:7. The video concludes with a closing screen displaying 'THANKS FOR WATCHING' in bold text on a black background, with an orange highlight box around 'THANKS' and an underline beneath the message.

The central concept is deriving a/b from (a+b)/(a-b) = m/n. The standard method uses cross-multiplication: n(a+b) = m(a-b), which simplifies to (m-n)a = (m+n)b, giving a/b = (m+n)/(m-n). For the example m=9, n=2: a/b = 11/7. The shortcut formula directly applies this result. Key teaching cues include variable setup, cross-multiplication to eliminate fractions, and verification via the shortcut. The lesson is concise and focused on one problem type with a clear worked example.

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