The aggregate number of whole numbers somewhere around100 and 200 which are…

Key idea: a number divisible by both 6 and 9 must be divisible by their least common multiple (LCM).

Step 1 — Find the LCM:

• LCM(6, 9) = 18

Step 2 — Find multiples of 18 between 100 and 200:

• Smallest multiple greater than 100: ceil(100 / 18) = 6 → 18 × 6 = 108

• Largest multiple less than 200: floor(200 / 18) = 11 → 18 × 11 = 198

• All multiples in this range: 108, 126, 144, 162, 180, 198

Step 3 — Count them:

• Number of multiples = 11 − 6 + 1 = 6

Conclusion: There are 6 whole numbers between 100 and 200 that are divisible by both 6 and 9.

Note: The original solution image concluded 5 incorrectly. This corrected solution shows the full counting method and the correct total of 6.