If x^2 – y^2 = 101, find the value of x² + y², given that x and y are natural…

2025

If x^2 – y^2 = 101, find the value of x² + y², given that x and y are natural numbers.

Answer: A. 5101x^2 – y^2 = 101 => (x+y)*(x-y) = 101*1 x+y = 101 x-y = 1 so, x = 51, y = 50 (x^2 + y^2) = 51^2 + 50^2 = 5101

  1. A.

    5101

  2. B.

    5050

  3. C.

    5501

  4. D.

    5010

Attempted by 26 students.

Show answer & explanation

Correct answer: A

x^2 – y^2 = 101

=> (x+y)*(x-y) = 101*1

x+y = 101

x-y = 1

so, x = 51, y = 50

(x^2 + y^2) = 51^2 + 50^2 = 5101

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