If x^2 – y^2 = 101, find the value of x² + y², given that x and y are natural…
2025
If x^2 – y^2 = 101, find the value of x² + y², given that x and y are natural numbers.
Answer: A. 5101 — x^2 – y^2 = 101 => (x+y)*(x-y) = 101*1 x+y = 101 x-y = 1 so, x = 51, y = 50 (x^2 + y^2) = 51^2 + 50^2 = 5101
- A.
5101
- B.
5050
- C.
5501
- D.
5010
Attempted by 26 students.
Show answer & explanation
Correct answer: A
x^2 – y^2 = 101
=> (x+y)*(x-y) = 101*1
x+y = 101
x-y = 1
so, x = 51, y = 50
(x^2 + y^2) = 51^2 + 50^2 = 5101
Loading lesson…