Longest commom Subsequence Part-1
Duration: 14 min
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- About Course: About the Course
- English Language: Vocabulary, Noun, Adjectives, Tenses, Pronoun, Adverb, Preposition, Conjunction, Active Passive Voice (Voice), Articles, Direct and Indirect Speech, Sentence Correction (Error Correction), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Sentence Completion (Fill in the blanks), Cloze Test (Cloze Passage)
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- Quantitative Aptitude: Ratio and Proportion (Ratios), Data Interpretation, Mixture and Alligation, Permutation and Combination, Number System, Sequence and Series (Series), Speed Time and Distance, Algebra, Speed Mathematics and Basic Mathematics, Percentage, Average, Time and Work, Simple Interest and Compound Interest, Profit and Loss, Age Problems, Partnership, Mensuration and Geometry, Probability, IBPS Specific Videos
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- Theory of Computation- Professional Knowledge: Introduction to TOC, Deterministic FA (DFA), Non-Deterministic FA, Regular Expressions, Regular Language Properties, Pushdown Automata & CFG, Turing Machines
- Compiler Design- Professional Knowledge: Intro to Compilers, Lexical Analysis, Grammar & CFG, Syntax Analysis: Top-Down, Intermediate Code Gen, Code Optimization
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- Full Length Mock Test:
AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
The lecture introduces the Longest Common Subsequence (LCS) problem, defining it as finding the longest subsequence common to a set of sequences, typically two. It highlights applications in bioinformatics (DNA comparison), computational linguistics, and version control systems like Git. The instructor then transitions to a concrete example involving two strings, X and Y, demonstrating the dynamic programming approach to solve the problem by constructing a matrix and tracing back the optimal path to identify the subsequence. The visual progression from abstract definitions to a biological diagram, and finally to a filled matrix, helps students understand both the 'why' and the 'how' of solving the LCS problem. The instructor meticulously fills the table, showing the recurrence relation in action. He uses red ink to highlight the values and arrows, ensuring clarity for the students.
Chapters
0:00 – 2:00 00:00-02:00
The video opens with a slide titled 'Longest common subsequence.' The text defines the LCS problem as finding the longest subsequence common to all sequences in a set, noting that it often involves just two sequences. The slide describes it as a classic computer science problem that forms the basis for data comparison programs like the `diff` utility. It further lists applications in computational linguistics and bioinformatics. Additionally, the text highlights its widespread use in revision control systems such as Git for reconciling multiple changes made to a revision-controlled collection of files. The instructor introduces the topic by reading these points, establishing the foundational context for the algorithm. He emphasizes that while the problem can involve a set of sequences, the most common case is comparing just two.
2:00 – 5:00 02:00-05:00
The presentation transitions to a diagram labeled 'Fig. 2. The double helical structure of DNA.' The instructor uses this biological example to explain the relevance of LCS in bioinformatics. He points out the sugar-phosphate backbone and the bases (A, T, C, G) that make up the DNA sequence. He draws a simplified linear representation of a DNA strand and writes a sequence like 'ATCG' to illustrate how biological data is encoded as strings. This visual aid helps students connect the abstract algorithm to real-world data processing tasks involving genetic sequences. He emphasizes that comparing these long strings of characters is exactly what the LCS algorithm is designed to handle efficiently. The diagram shows the helical structure with labeled components like Phosphorus, Carbon, Hydrogen, and Oxygen, providing a detailed scientific context.
5:00 – 10:00 05:00-10:00
The lecture returns to the text slide, specifically underlining the phrase 'often just two sequences.' A new problem statement appears: 'Consider two strings X = 'A, B, C, B, D, A, B' and Y = 'B, D, C, A, B, A'. Find the longest common subsequence?' The instructor sets up a dynamic programming table (matrix) with rows labeled 0 to 7 and columns labeled 0 to 6. He initializes the first row and column with zeros. He begins filling the table, explaining the logic: if the characters at the current row and column match, the value is the diagonal value plus one; if they do not match, it is the maximum of the top or left cell. He fills the first row where 'A' matches the last column, resulting in values like 0, 0, 0, 0, 1, 1, 1. In the second row for 'B', he finds a match at the first column, setting the value to 1, and propagates the maximums across the row. He methodically calculates values for each cell, showing how the length of the common subsequence grows as he moves through the grid. He writes the numbers in red ink, making them stand out against the grid lines.
10:00 – 13:47 10:00-13:47
The instructor continues to fill the matrix, completing the dynamic programming table. He demonstrates the backtracking process to find the actual subsequence. He draws arrows indicating the path from the bottom-right cell back to the top-left. By following the diagonal moves where characters matched, he identifies the sequence 'B, C, B, A'. He circles the corresponding characters in string Y and writes the number '4' at the top right, indicating the length of the longest common subsequence. This final step solidifies the method for extracting the solution from the computed table. He specifically traces the path through cells (2,1), (3,3), (4,5), and (6,6) to confirm the characters. The final result is clearly displayed, showing both the length and the specific sequence. The table is fully populated with values like 1, 2, 3, and 4, culminating in the final answer. He circles the final answer '4' to emphasize the result.
The lesson effectively bridges theoretical definition with practical application and algorithmic implementation. It starts by contextualizing LCS within computer science and biology, then moves to a step-by-step walkthrough of the dynamic programming algorithm. The visual progression from abstract definitions to a biological diagram, and finally to a filled matrix, helps students understand both the 'why' and the 'how' of solving the LCS problem. The instructor's methodical filling of the table and subsequent backtracking provide a clear template for solving similar problems in exams. The specific example of DNA sequences reinforces the real-world importance of the algorithm. The use of a grid and arrows makes the abstract concept of dynamic programming concrete and easy to follow.