Fourier series of the periodic function (period 2π) defined by f(x) = {0, −π <…

GATE · 1993 · CS · Question 1 subpartsModified — slightly modified from the official paper; see the solution

Fourier series of the periodic function (period 2π) defined by f(x) = {0, −π < x < 0; x, 0 < x < π} is π/4 + Σₙ₌₁∞[(1/(πn²))(cos nπ − 1) cos nx − (1/n) cos nπ sin nx]. But putting x = π, we get the sum of the series 1 + 1/3² + 1/5² + 1/7² + … is

  1. A.

    π²/4

  2. B.

    π²/6

  3. C.

    π²/8

  4. D.

    π²/12

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