Fourier series of the periodic function (period 2π) defined by f(x) = {0, −π <…
GATE · 1993 · CS · Question 1 subpartsModified — slightly modified from the official paper; see the solution
Fourier series of the periodic function (period 2π) defined by f(x) = {0, −π < x < 0; x, 0 < x < π} is π/4 + Σₙ₌₁∞[(1/(πn²))(cos nπ − 1) cos nx − (1/n) cos nπ sin nx]. But putting x = π, we get the sum of the series 1 + 1/3² + 1/5² + 1/7² + … is
- A.
π²/4
- B.
π²/6
- C.
π²/8
- D.
π²/12
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