Consider the following expression: I. A⋀B II. A⋁B III.~A⋀B IV. TRUE V. FALSE…
Consider the following expression:
I. A⋀B
II. A⋁B
III.~A⋀B
IV. TRUE
V. FALSE
The number of expression(s) above that are logically implied by (A⋀B)⋀(~A→~B) is
Answer: C. 3 — (c) (A⋀B)⋀(~A→~B) AB⋀A+B'=A⋀B A⋀B→(A⋀B)≡TRUE A⋀B→(A⋁B)≡TRUE A⋀B→TRUE≡TRUE
- A.
1
- B.
2
- C.
3
- D.
4
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Correct answer: C
(c)
(A⋀B)⋀(~A→~B)
AB⋀A+B'=A⋀B
A⋀B→(A⋀B)≡TRUE
A⋀B→(A⋁B)≡TRUE
A⋀B→TRUE≡TRUE
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