Upper Triangular Matrix | CMO
Duration: 11 min
This video lesson is available to enrolled students.
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This lecture provides a comprehensive guide on storing upper triangular matrices in one-dimensional arrays, focusing specifically on column-major order. The instructor begins by defining the structure of an upper triangular matrix where all elements below the main diagonal are zero. He demonstrates how to represent a 4x4 matrix and identifies that only elements where the row index is less than or equal to the column index (i <= j) require storage. The lecture derives the formula n(n+1)/2 to calculate the total number of non-zero elements needed for storage. A significant portion of the video is dedicated to mapping these 2D matrix elements into a linear array using column-major order, where columns are filled sequentially. The instructor then transitions to practical application by calculating memory addresses for specific elements, utilizing a base address of 1000 and an element size of 8 bytes. The session culminates in a detailed derivation of the general formula for locating any element A[i][j] within this storage scheme, followed by a worked example calculating the address of element a34.
Chapters
0:00 – 2:00 00:00-02:00
The lecture opens with the instructor introducing the topic of 'Upper Triangular Matrix Storage in Array' on a digital whiteboard. He visually constructs the concept by drawing a large bracket and then sketching a 4x4 matrix structure. The instructor labels the rows and columns with indices ranging from 1 to 4, populating the matrix with variables a_ij. Crucially, he highlights that elements below the main diagonal are zero, specifically writing '0' in positions where the row index exceeds the column index. This establishes the fundamental definition of an upper triangular matrix, setting the stage for discussing efficient storage methods by ignoring these zero elements.
2:00 – 5:00 02:00-05:00
The instructor focuses on the storage logic, explaining that elements where i > j are zero and do not need to be stored in memory. He draws a diagonal line to separate the non-zero upper triangle from the zero lower triangle. The lecture then introduces column-major order as the specific storage method, writing 'Column Major Order' on the board. He calculates the total number of elements to be stored using the formula n(n+1)/2, substituting n=4 to show that 4(5)/2 equals 10 elements. The instructor begins drawing a one-dimensional array to visualize how these non-zero elements will be mapped sequentially from the matrix columns.
5:00 – 10:00 05:00-10:00
This section details the memory address calculation process. The instructor sets specific parameters: a Base Address of 1000 and an Element Size of 8 bytes. He poses the problem of finding the location of element A[3][7], though later examples use indices within a 4x4 context. The instructor derives the offset by summing elements in previous columns, writing '1+2+3' to demonstrate counting preceding elements. He writes the general formula Loc(A[i][j]) = Base Address + [((j-lb2)(j-lb2+1))/2 + (i-lb1)] * Element Size. The derivation connects the visual matrix structure to algebraic terms, showing how row and column indices determine the offset from the base address.
10:00 – 11:18 10:00-11:18
In the final segment, the instructor applies the derived formula to calculate the specific memory address for element a34. The board displays the step-by-step arithmetic: substituting values into the column-major formula, calculating (4-1)(4-1+1)/2 which equals 6. The final calculation is shown as 1000 + [(4-1)(4-1+1)/2 + (3-1)] * 2, resulting in the address 1016. The instructor concludes by reinforcing how the two-dimensional matrix structure is flattened into a one-dimensional array using column-major order, ensuring students understand both the theoretical storage count and the practical address computation.
The lecture systematically progresses from defining the upper triangular matrix to implementing its storage in a linear array. Key concepts include the exclusion of zero elements below the diagonal, the use of column-major order for mapping 2D indices to 1D positions, and the mathematical derivation of memory addresses. The instructor emphasizes that storage is optimized by only keeping non-zero elements, reducing the space requirement from n^2 to n(n+1)/2. The practical application involves calculating offsets based on the number of elements in preceding columns, a critical skill for understanding array indexing in sparse matrix representations. The worked example of finding the address for a34 solidifies the theoretical formula with concrete arithmetic, demonstrating how base addresses and element sizes factor into the final memory location.