A subnet has been assigned a subnet mask of 255.255.255.192. What is the…

Answer: 62 usable hosts.

Explanation:

• Determine the prefix length: 255.255.255.192 corresponds to /26.

• Calculate host bits: 32 total bits − 26 network bits = 6 host bits.

• Compute usable hosts: 2^6 − 2 = 64 − 2 = 62 (subtract the network and broadcast addresses).

Common related masks (to explain the other numeric choices):

• 14 = /28 (255.255.255.240), host bits = 4 → 2^4 − 2 = 14.

• 30 = /27 (255.255.255.224), host bits = 5 → 2^5 − 2 = 30.

• 126 = /25 (255.255.255.128), host bits = 7 → 2^7 − 2 = 126.