Finding ratio of 2 numbers from their sum & difference
Duration: 3 min
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Module outline
- Language Skills (English): Vocabulary, Verbal Analogy (Word Based Analogy), Noun, Pronoun, Verb, Adjectives, Adverb, Preposition, Articles, Conjunction, Tenses, Modals, Subject Verb Agreement (Verb Noun Agreement), Determiner, Active Passive Voice (Voice), Direct and Indirect Speech, Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Construction, Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Cloze Test (Cloze Passage)
- General Aptitude (Quantitative Ability): Percentage, Ratio and Proportion (Ratios), Average, Profit and Loss, Simple Interest and Compound Interest, Time and Work, Pipe and Cistern, Speed Time and Distance, Mixture and Alligation, Age Problems, Partnership, Number System, HCF LCM, Divisibility Rules, Powers and Exponents (Surds and Indices), Algebra, Data Interpretation, Statistics, Sequence and Series (Series), Logarithm, Arithmetic, Speed Mathematics and Basic Mathematics
- General Aptitude (Reasoning Ability): Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Syllogisms, Blood Relations, Directions (Direction Test), Ranking, Order and Sequence, Inequality, Logical Sequence Of Words, Seating Arrangements, Puzzle Solving (Puzzles), Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Cubes & Dices, Venn Diagram, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Selection Decision Table (Decision Making), Analytical Reasoning (Counting Figures Reasoning), Clock, Calendar, Data Sufficiency, Analogy
- Technical Skills MCQ - Data Structure: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
- Technical Skills MCQ - Networking: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, Application Layer, Mobile Technology, Network Security
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- Technical Skills MCQ - DBMS: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), File Organization & Indexing, Relational Algebra, SQL, Transaction Management, Concurrency Control, Database Recovery, Database Security & Authorization, NoSQL
- Technical Skills MCQ - Software Engineering: Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
- Technical Skills MCQ - Cloud Computing: Emerging Tech Trends, Cloud Computing and IoT
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- Technical Skills (Coding): Coding Questions by Yash Sir, C Programming by Yash Sir, Programming in C++, Java, Python for Placements by Yash Sir, Object Oriented Programming (OOPS)
AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
This short math lesson teaches how to find the ratio of two numbers when given the ratio of their sum and difference. The instructor introduces variables a and b, sets up (a+b)/(a-b) = given ratio, then solves the example where sum:diff = 9:2. Cross-multiplication gives 2(a+b) = 9(a-b), leading to 11b = 7a and a/b = 11/7. A shortcut formula a/b = (9+2)/(9-2) confirms the result 11:7. The video ends with a thanks screen.
Chapters
0:00 – 2:00 00:00-02:00
The lesson opens with the title 'Finding Ratio of Numbers Given Ratio of Sum & Difference'. The instructor defines two numbers as a and b, writes 'a, b = x ?', and establishes the core relationship (a+b)/(a-b) = given ratio, with a circled 'a/b' indicating the target. The example question appears: 'Ratio of sum & difference of two numbers is 9 : 2. Find the ratio of numbers.' The instructor writes 'Sum/Diff = 9/2' and begins forming the equation (a+b)/(a-b) = 9/2, setting up the algebraic method.
2:00 – 3:11 02:00-03:11
The instructor solves the equation by cross-multiplying: 2(a+b) = 9(a-b). Expanding and simplifying yields 11b = 7a, so a/b = 11/7. A shortcut formula is then shown: a/b = (9+2)/(9-2) = 11/7, confirming the ratio of numbers is 11:7. The video concludes with a closing screen displaying 'THANKS FOR WATCHING' in bold text on a black background, with an orange highlight box around 'THANKS' and an underline beneath the message.
The central concept is deriving a/b from (a+b)/(a-b) = m/n. The standard method uses cross-multiplication: n(a+b) = m(a-b), which simplifies to (m-n)a = (m+n)b, giving a/b = (m+n)/(m-n). For the example m=9, n=2: a/b = 11/7. The shortcut formula directly applies this result. Key teaching cues include variable setup, cross-multiplication to eliminate fractions, and verification via the shortcut. The lesson is concise and focused on one problem type with a clear worked example.