Short Tricks to Combine Two or More Ratios
Duration: 16 min
This video lesson is available to enrolled students.
Inside: a video lesson and guided study material.
Module outline
- Child Development and Pedagogy / बाल विकास एवं शिक्षाशास्त्र: Concept of Development / विकास की अवधारणा, Psychological Theories of Development / विकास के मनोवैज्ञानिक सिद्धांत, Individual Differences, Personality and Gender / व्यक्तिगत भिन्नताएँ, व्यक्तित्व एवं जेंडर, Intelligence and Creativity / बुद्धि एवं सृजनात्मकता, Learning and Its Theories / अधिगम एवं इसके सिद्धांत, How Children Think and Learn / बालक कैसे सोचते एवं सीखते हैं, Emotion, Motivation, Mental Health and Guidance / संवेग, अभिप्रेरणा, मानसिक स्वास्थ्य एवं निर्देशन, Inclusive Education / समावेशी शिक्षा, Teaching-Learning Process / शिक्षण-अधिगम प्रक्रिया, Teaching Methods and Strategies / शिक्षण विधियाँ एवं रणनीतियाँ, Assessment and Evaluation / आकलन एवं मूल्यांकन, Curriculum and School Activities / पाठ्यचर्या और विद्यालयी गतिविधियाँ, Lesson Planning and Teaching Skills / पाठ योजना और शिक्षण कौशल, Teaching Resources and Educational Technology / शिक्षण संसाधन और शैक्षिक प्रौद्योगिकी, Educational Thinkers, Aims and National Policies / शैक्षिक विचारक, उद्देश्य एवं राष्ट्रीय नीतियाँ, Classroom Management and Communication / कक्षा प्रबंधन और सम्प्रेषण, Teacher Identity and Professional Development / शिक्षक पहचान और व्यावसायिक विकास, Social Science Pedagogy / सामाजिक विज्ञान शिक्षणशास्त्र, Social and Political Life / सामाजिक एवं राजनीतिक जीवन, Science Pedagogy / विज्ञान शिक्षण शास्त्र, Life Skills, Values, Peace and Environmental Education / जीवन कौशल, मूल्य, शांति एवं पर्यावरण शिक्षा, Constitution, Commissions, Acts and Schemes in Education / संविधान, आयोग, अधिनियम एवं योजनाएँ
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AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
This lecture by Yash Jain on Ratio and Proportion teaches a systematic shortcut for combining two or more ratios that share common terms. The instructor begins with the foundational example of finding a:b:c given a:b = 2:3 and b:c = 5:6. The core method involves converting the ratios into fractions (a/b and b/c), identifying the common variable, and scaling each ratio so that the shared term has an equal value in both. In the first example, multiplying a/b by 5 and b/c by 3 makes 'b' equal to 15 in both, yielding a:b:c = 10:15:18, which simplifies to 2:3:6. The lesson then progresses to more complex chains, such as finding a:b:c:d from three ratios (a:b = 3:4, b:c = 5:6, c:d = 2:3). Here, the instructor uses a tabular or grid method to align all common terms horizontally. By cross-multiplying the numerators and denominators across the chain, the combined ratio is calculated as 3×5×2 : 4×5×2 : 4×6×2 : 4×6×3, resulting in 30:40:48:72. This is then simplified by dividing by the greatest common divisor to reach the final answer of 15:20:24:36. The video emphasizes that the key to these tricks is maintaining the proportional relationship while making common terms identical, allowing for a direct read-off of the combined ratio.
Chapters
0:00 – 2:00 00:00-02:00
The video opens with a title slide for 'Ratio & Proportion' by Yash Jain. The first problem is presented: find a:b:c if a:b = 2:3 and b:c = 5:6. The instructor writes these as fractions, a/b = 2/3 and b/c = 5/6, and begins mapping the values for each variable to identify the common term 'b'.
2:00 – 5:00 02:00-05:00
The instructor demonstrates the scaling method for the first example. To make 'b' equal, a/b is multiplied by 5 to become 10/15, and b/c is multiplied by 3 to become 15/18. This allows the combined ratio a:b:c to be written as 10:15:18, which is then simplified by dividing all terms by 5 to reach the final answer of 2:3:6.
5:00 – 10:00 05:00-10:00
A second example is solved where a:b = 3:4 and b:c = 7:8. Using the same cross-multiplication logic, the ratios are adjusted to a/b = 21/28 and b/c = 28/32, resulting in a combined ratio of 21:28:32. The instructor then introduces a more complex four-variable problem involving three ratios to find a:b:c:d.
10:00 – 15:00 10:00-15:00
The instructor sets up a four-column table for the problem where a:b = 3:4, b:c = 5:6, and c:d = 2:3. Using a grid layout with empty boxes for unknowns, the instructor shows how to multiply terms horizontally across the chain. The products are calculated as 3×5×2 : 4×5×2 : 4×6×2 : 4×6×3, leading to the intermediate ratio 30:40:48:72.
15:00 – 15:38 15:00-15:38
The final steps of the four-variable problem are shown. The intermediate ratio 30:40:48:72 is simplified by dividing all terms by 2 (indicated by a '← /2' note). The final boxed answer is presented as 15:20:24:36, with the first two terms circled to emphasize the successful combination of the ratio chain.
The lecture provides a clear, step-by-step progression from simple two-ratio combinations to complex four-variable chains. The central takeaway is the 'common term' rule: by scaling adjacent ratios so that their shared variable matches, students can directly construct the combined ratio. The transition from manual fraction manipulation to a tabular grid method is a key pedagogical shift, offering a more organized 'shortcut' for exams. The use of visual cues like circling common terms and drawing arrows between grid cells helps students track the multiplication steps, ensuring that no term is missed in long ratio chains.