Stack Practice questions
Duration: 5 min
This video lesson is available to enrolled students.
Inside: a video lesson and guided study material.
Module outline
- Communication Round: Vocabulary, Subject Verb Agreement (Verb Noun Agreement), Tenses, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Cloze Test (Cloze Passage), Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Direct and Indirect Speech, Active Passive Voice (Voice), Verbal Analogy (Word Based Analogy), Articles, Preposition, Conjunction, Sentence Construction, English Writing Ability, Communication Assessment
- Quantitative Aptitude: Ratio and Proportion (Ratios), Divisibility Rules, Data Interpretation, Mixture and Alligation, Permutation and Combination, Logarithm, Number System, HCF LCM, Speed Time and Distance, Percentage, Average, Powers and Exponents (Surds and Indices), Time and Work, Mensuration and Geometry, Age Problems, Pipe and Cistern, Probability, Profit and Loss, Simple Interest and Compound Interest, Algebra
- Analytical and Logical Reasoning: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Data Sufficiency, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Directions (Direction Test), Ranking, Order and Sequence, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Selection Decision Table (Decision Making), Logical Sequence Of Words, Puzzle Solving (Puzzles), Syllogisms, Seating Arrangements, Calendar, Clock, Blood Relations, Cubes & Dices, Venn Diagram, Analytical Reasoning (Counting Figures Reasoning)
- Cognizant Gaming Aptitude: Gamified / Game Based Aptitude
- Java (Cluster 1): Java
- ANSI SQL MySQL (Cluster 1,2,3): SQL
- HTML, CSS, JavaScript (Cluster 1,3): HTML, CSS, JavaScript
- Python (Cluster 2): Python for Placements by Yash Sir
- Cloud Fundamentals (Cluster 2): Emerging Tech Trends
- C# (Cluster 3): C#
- OOPs: Object Oriented Programming (OOPS)
- Technical Assessment (Coding): Coding Questions by Yash Sir, C Programming by Yash Sir, Programming in C++, Pseudo Codes
- Data Structures: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
- DBMS: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, Relational Calculus, Transaction Management, Concurrency Control, Database Recovery, ORDBMS, Database Security & Authorization, Query Processing & Optimization, Enhanced Data Models, Data Warehousing & Mining, Big Data Systems, NoSQL
- Operating Systems: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Deadlock, Threads & Process Creation, Memory Management, Virtual Memory, Disc Scheduling, File Management, Windows OS, Linux OS, Security, Distributed Systems, Virtual Machines
- Computer Networks: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Mobile Technology, Cloud Computing and IoT, Cyber and Info Security
AI summary & chapters
AI Summary
An AI-generated summary of this video lecture.
This educational video demonstrates how to trace the execution of a recursive C function to determine its output. The instructor presents a code snippet containing a function named `print(int n)` which includes a base case check `if (n > 4000)`. The function prints the current value of `n`, calls itself recursively with `2*n`, and then prints `n` again. The `main` function initiates this process by calling `print(1000)`. The lecture focuses on manually stepping through the recursion stack to predict the sequence of numbers printed to the console.
Chapters
0:00 – 2:00 00:00-02:00
The instructor begins by analyzing the provided C code, specifically the `print` function. He writes `print(1000)` on the whiteboard to represent the initial call from `main`. He evaluates the condition `if (n > 4000)` for `n=1000`, marking it as false. Consequently, the code proceeds to the first `printf("%d ", n)`, which outputs `1000`. He then identifies the next step as a recursive call `print(2*n)`, which becomes `print(2000)`. He starts drawing a tree diagram to visualize the call stack, placing `1000` as the root and `print(2000)` as the child node.
2:00 – 4:37 02:00-04:37
Continuing the trace, the instructor evaluates `print(2000)`. The condition `2000 > 4000` is false, so it prints `2000` and calls `print(4000)`. Next, `print(4000)` is evaluated; `4000 > 4000` is false, so it prints `4000` and calls `print(8000)`. The instructor notes that `print(8000)` satisfies the base case `8000 > 4000`, causing the function to return immediately without printing. The execution then unwinds. The second `printf` in `print(4000)` executes, printing `4000`. Then the second `printf` in `print(2000)` executes, printing `2000`. Finally, the second `printf` in `print(1000)` executes, printing `1000`. The final sequence is `1000 2000 4000 4000 2000 1000`, corresponding to option (B).
The lesson effectively illustrates the two-phase nature of recursion: the forward pass where code executes before the recursive call, and the backward pass where code executes after the call returns. By tracing the specific values `1000`, `2000`, `4000`, and the base case `8000`, the instructor demonstrates how the first set of prints creates an ascending sequence while the return phase creates a descending sequence, resulting in a symmetric output pattern.