recursive functions

Duration: 7 min

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Module outline

  1. Communication Round: Vocabulary, Subject Verb Agreement (Verb Noun Agreement), Tenses, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Cloze Test (Cloze Passage), Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Direct and Indirect Speech, Active Passive Voice (Voice), Verbal Analogy (Word Based Analogy), Articles, Preposition, Conjunction, Sentence Construction, English Writing Ability, Communication Assessment
  2. Quantitative Aptitude: Ratio and Proportion (Ratios), Divisibility Rules, Data Interpretation, Mixture and Alligation, Permutation and Combination, Logarithm, Number System, HCF LCM, Speed Time and Distance, Percentage, Average, Powers and Exponents (Surds and Indices), Time and Work, Mensuration and Geometry, Age Problems, Pipe and Cistern, Probability, Profit and Loss, Simple Interest and Compound Interest, Algebra
  3. Analytical and Logical Reasoning: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Data Sufficiency, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Directions (Direction Test), Ranking, Order and Sequence, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Selection Decision Table (Decision Making), Logical Sequence Of Words, Puzzle Solving (Puzzles), Syllogisms, Seating Arrangements, Calendar, Clock, Blood Relations, Cubes & Dices, Venn Diagram, Analytical Reasoning (Counting Figures Reasoning)
  4. Cognizant Gaming Aptitude: Gamified / Game Based Aptitude
  5. Java (Cluster 1): Java
  6. ANSI SQL MySQL (Cluster 1,2,3): SQL
  7. HTML, CSS, JavaScript (Cluster 1,3): HTML, CSS, JavaScript
  8. Python (Cluster 2): Python for Placements by Yash Sir
  9. Cloud Fundamentals (Cluster 2): Emerging Tech Trends
  10. C# (Cluster 3): C#
  11. OOPs: Object Oriented Programming (OOPS)
  12. Technical Assessment (Coding): Coding Questions by Yash Sir, C Programming by Yash Sir, Programming in C++, Pseudo Codes
  13. Data Structures: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  14. DBMS: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, Relational Calculus, Transaction Management, Concurrency Control, Database Recovery, ORDBMS, Database Security & Authorization, Query Processing & Optimization, Enhanced Data Models, Data Warehousing & Mining, Big Data Systems, NoSQL
  15. Operating Systems: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Deadlock, Threads & Process Creation, Memory Management, Virtual Memory, Disc Scheduling, File Management, Windows OS, Linux OS, Security, Distributed Systems, Virtual Machines
  16. Computer Networks: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Mobile Technology, Cloud Computing and IoT, Cyber and Info Security
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

The video lecture focuses on analyzing a recursive pseudo-code function named Print_somthing(a, i, j) to determine its output. The instructor sets up a specific scenario using an integer array a containing the values [10, 18, 7, 16, 22, 15] at indices 0 through 5. The function operates by comparing the element at the start index i with the element at the end index j. If the element at i is strictly less than the element at j, the function recursively calls itself with i+1, effectively discarding the smaller element on the left. If the element at i is greater than or equal to the element at j, it calls itself with j-1, discarding the smaller element on the right. This process repeats until the indices converge (i == j), at which point the remaining element is printed. The instructor demonstrates that this logic is a method for finding the maximum element in an array.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The instructor introduces the problem statement 'Find the output of the following pseudo code?' and displays the function definition void Print_somthing(a, i, j). He draws a horizontal array diagram labeled a with indices 0 to 5. He writes memory addresses like 1000, 1004 above the boxes to indicate contiguous memory, then fills the boxes with the values 10, 18, 7, 16, 22, 15. He writes the initial call Print_somthing(a, 0, 5) at the bottom. He explains the base case if (i == j) which triggers a printf of a[i] and returns. He then explains the Else block containing the comparison if (a[i] < a[j]).

  2. 2:00 – 5:00 02:00-05:00

    The instructor performs the first few recursive steps. He compares a[0] (10) and a[5] (15). Since 10 < 15 is true, he writes Print_somthing(a, 1, 5). Next, he compares a[1] (18) and a[5] (15). Since 18 < 15 is false, he executes the Else branch and writes Print_somthing(a, 1, 4). He continues tracing: comparing a[1] (18) and a[4] (22), where 18 < 22 is true, leading to Print_somthing(a, 2, 4). Then he compares a[2] (7) and a[4] (22), where 7 < 22 is true, leading to Print_somthing(a, 3, 4). Finally, he compares a[3] (16) and a[4] (22), where 16 < 22 is true, leading to Print_somthing(a, 4, 4).

  3. 5:00 – 7:12 05:00-07:12

    The instructor finalizes the execution trace. With the call Print_somthing(a, 4, 4), the condition i == j (4 == 4) becomes true. He circles the base case block and writes 22 -> output on the board, indicating that a[4] is the result. He verbally explains that the algorithm works by eliminating the smaller of the two boundary elements in each step, ensuring the maximum value remains until the indices meet. He confirms the final output is 22.

The video provides a step-by-step walkthrough of a recursive algorithm designed to find the maximum value in an array. By comparing boundary elements and discarding the smaller one, the search space narrows until a single element remains. The instructor uses a concrete example with the array [10, 18, 7, 16, 22, 15] to demonstrate that the function correctly identifies 22 as the maximum element.

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