BST Practice Question

Duration: 2 min

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Module outline

  1. About Course: About the Course
  2. Paper-2 | Programming & Data Structures: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling, Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  3. Paper-2 | Databases / DBMS & SQL: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, SQL, Relational Calculus, Transaction Management, Concurrency Control
  4. Paper-2 | Algorithms: Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Dynamic Programming, Minimum Spanning Trees, Shortest Path Algos
  5. Paper-2 | Computer Networks & Security: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware Basics, Network Access Technologies, Network Security
  6. Paper-2 | Digital Logic: Digital Systems & Boolean Basics, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits, Number System, Number Representation, Floating Point Rep
  7. Paper-2 | Operating System: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management
  8. Paper-2 | Theory of Computation: Introduction to TOC, Deterministic FA (DFA), Non-Deterministic FA, Regular Expressions, Grammar, Regular Language Properties, Moore & Mealy Machines, Pushdown Automata & CFG, Turing Machines
  9. Paper-2 | Computer Organization & Architecture: Basics of COA, Cache Memory Organization, Input Output Organisation, Pipelining, Instr Formats & Modes, Control Unit Design, Programming the Basic Computer
  10. Paper-2 | Compiler Design: Intro to Compilers, Lexical Analysis, Grammar & CFG, Syntax Analysis: Top-Down, Syntax Analysis: Bottom-Up, Semantic Analysis & SDT, Intermediate Code Gen, Code Optimization, Run Time Environment
  11. Paper-1 | General Awareness: Polity, Physics, Biology, Chemistry, Static General Knowledge, GK- Current Affairs, History, Geography, Indian Economy, Environment
  12. Paper-1 | Logical Reasoning: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Data Interpretation, Blood Relations, Syllogisms, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Selection Decision Table (Decision Making), Clock, Calendar, Cubes & Dices, Directions (Direction Test), Analogy, Seating Arrangements, Analytical Reasoning (Counting Figures Reasoning)
  13. Paper-1 | Quantitative Aptitude: Ratio and Proportion (Ratios), Mixture and Alligation, Permutation and Combination, Number System, HCF LCM, Speed Time and Distance, Average, Age Problems, Percentage, Profit and Loss, Time and Work, Pipe and Cistern, Simple Interest and Compound Interest, Powers and Exponents (Surds and Indices), Mensuration and Geometry, Probability, Statistics, Arithmetic, Algebra
  14. Paper-1 | English: Vocabulary, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Construction, Cloze Test (Cloze Passage)
  15. Coal India Previous Year Paper:
  16. Engineering Mathematics: Set Theory, Relations, Functions, Graph Theory, Group Theory, Propositional and Predicate Logic, Linear Algebra, Calculus
  17. Coal India Mock Test:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

The video lecture addresses a specific scenario in Binary Search Tree (BST) deletion: removing a node that has both left and right children non-empty. The instructor explains that in this case, the inorder successor (or predecessor) must be used to replace the deleted node. He presents a multiple-choice question asking for the true statement regarding the properties of the inorder successor. The options explore whether the successor is always a leaf, has an empty left child, is an ancestor, or has an empty right child. The instructor uses a whiteboard drawing to illustrate the BST structure and the traversal logic required to find the successor.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The instructor begins by stating the problem context: deleting a node with two children. He draws a BST on the whiteboard to illustrate. The tree has a root node 10, a left child 1, and a right child 15. The node 15 has a right child 20, which in turn has a right child 3. He writes the inorder traversal sequence "1 10 15 20 3" to show the order. He explains that the inorder successor of a node is the smallest node in its right subtree. He traces the path to find the successor, emphasizing that one goes to the right child and then keeps moving left until no left child exists. He analyzes the options, noting that the successor is found by going left as much as possible, meaning it cannot have a left child itself. He underlines option (B) and discusses why other options like (C) and (D) are incorrect.

  2. 2:00 – 2:10 02:00-02:10

    The instructor concludes the analysis. He confirms that the inorder successor is always either a leaf node (no children) or a node with an empty left child (but potentially a right child). He explicitly marks option (B) "Inorder successor is always either a leaf node or a node with empty left child" as the correct answer. He reinforces that if the successor had a left child, that child would be smaller and thus the true successor, contradicting the definition. He circles the correct option and summarizes the key takeaway for exam preparation.

The lecture clarifies a key property of BST deletion: the inorder successor of a node with two children is guaranteed to have no left child. This is because the successor is defined as the smallest value in the right subtree, found by traversing left until a leaf or a node with only a right child is reached. This property simplifies the deletion logic, as the successor can be easily removed or spliced into the tree without violating BST properties.

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