Stack Practice questions

Duration: 5 min

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Inside: a video lesson and guided study material.

Module outline

  1. About Course: About the Course
  2. Paper-2 | Programming & Data Structures: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling, Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  3. Paper-2 | Databases / DBMS & SQL: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, SQL, Relational Calculus, Transaction Management, Concurrency Control
  4. Paper-2 | Algorithms: Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Dynamic Programming, Minimum Spanning Trees, Shortest Path Algos
  5. Paper-2 | Computer Networks & Security: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware Basics, Network Access Technologies, Network Security
  6. Paper-2 | Digital Logic: Digital Systems & Boolean Basics, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits, Number System, Number Representation, Floating Point Rep
  7. Paper-2 | Operating System: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management
  8. Paper-2 | Theory of Computation: Introduction to TOC, Deterministic FA (DFA), Non-Deterministic FA, Regular Expressions, Grammar, Regular Language Properties, Moore & Mealy Machines, Pushdown Automata & CFG, Turing Machines
  9. Paper-2 | Computer Organization & Architecture: Basics of COA, Cache Memory Organization, Input Output Organisation, Pipelining, Instr Formats & Modes, Control Unit Design, Programming the Basic Computer
  10. Paper-2 | Compiler Design: Intro to Compilers, Lexical Analysis, Grammar & CFG, Syntax Analysis: Top-Down, Syntax Analysis: Bottom-Up, Semantic Analysis & SDT, Intermediate Code Gen, Code Optimization, Run Time Environment
  11. Paper-1 | General Awareness: Polity, Physics, Biology, Chemistry, Static General Knowledge, GK- Current Affairs, History, Geography, Indian Economy, Environment
  12. Paper-1 | Logical Reasoning: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Data Interpretation, Blood Relations, Syllogisms, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Selection Decision Table (Decision Making), Clock, Calendar, Cubes & Dices, Directions (Direction Test), Analogy, Seating Arrangements, Analytical Reasoning (Counting Figures Reasoning)
  13. Paper-1 | Quantitative Aptitude: Ratio and Proportion (Ratios), Mixture and Alligation, Permutation and Combination, Number System, HCF LCM, Speed Time and Distance, Average, Age Problems, Percentage, Profit and Loss, Time and Work, Pipe and Cistern, Simple Interest and Compound Interest, Powers and Exponents (Surds and Indices), Mensuration and Geometry, Probability, Statistics, Arithmetic, Algebra
  14. Paper-1 | English: Vocabulary, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Construction, Cloze Test (Cloze Passage)
  15. Coal India Previous Year Paper:
  16. Engineering Mathematics: Set Theory, Relations, Functions, Graph Theory, Group Theory, Propositional and Predicate Logic, Linear Algebra, Calculus
  17. Coal India Mock Test:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

The video presents a C programming problem asking students to predict the output of a recursive function f(n) called with the argument 11. The instructor systematically traces the execution of the code, analyzing the base cases and recursive steps. He writes down the call tree on the whiteboard, breaking down f(11) into smaller sub-problems like f(5) and f(6). By evaluating each recursive call step-by-step, determining return values based on integer division and modulo operations, he calculates the final result. The process involves checking conditions like n <= 1 and n % 2 == 0 to decide the return path. The final output is determined to be 5, corresponding to option (D).

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The instructor introduces the problem "Predict the output of following program" and displays the C code on screen. He starts tracing the function f(11) written on the board. He evaluates the first condition if(n <= 1) as false for 11. Then he checks if(n%2 == 0), noting that 11 is odd, so this is also false. Consequently, he moves to the final return statement return f(n/2) + f(n/2+1), substituting 11 to get return f(5) + f(6). He begins expanding f(5) by writing Ret f(2) + f(3) underneath it, indicating the next level of recursion. He then analyzes f(2), checking 2 <= 1 (false) and 2%2 == 0 (true), leading to return f(1). He establishes that f(1) returns 1 because 1 <= 1 is true, writing f(2) = 1 on the side.

  2. 2:00 – 5:00 02:00-05:00

    Continuing the trace, the instructor evaluates f(3). Since 3 is odd, it hits the final return statement: return f(1) + f(2). Using the previously calculated values where f(1) = 1 and f(2) = 1, he determines f(3) = 2. He writes f(3) = 2 on the board. Returning to f(5), he sums the results of its children: f(2) + f(3) becomes 1 + 2, so f(5) = 3. Next, he analyzes f(6). Since 6 is even, the condition n%2 == 0 is true, so it returns f(6/2) which is f(3). Since f(3) is already known to be 2, f(6) = 2. Finally, he combines the results for the initial call: f(11) = f(5) + f(6) becomes 3 + 2, resulting in 5. He writes f(11) = 5 clearly on the board.

  3. 5:00 – 5:08 05:00-05:08

    The instructor concludes the problem by confirming the calculated result is 5. He points to option (D) 5 and places a checkmark next to it, indicating it is the correct answer. He briefly dismisses the other options, crossing out (A) Stack Overflow, (B) 3, and (C) 4 to show they are incorrect. The video ends with the final answer selected.

The lecture demonstrates a methodical approach to solving recursive function problems by manually tracing the call stack. The instructor breaks down complex calls into simpler sub-problems, utilizing a top-down expansion strategy. By calculating base cases first and working backwards up the recursion tree, he avoids stack overflow errors and correctly computes the final integer value. This step-by-step evaluation highlights the importance of understanding integer division and modulo operators in C recursion.

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