Multiplexer Expansion Part-2

Duration: 6 min

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Module outline

  1. About Course: About the Course
  2. Paper-2 | Programming & Data Structures: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling, Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  3. Paper-2 | Databases / DBMS & SQL: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, SQL, Relational Calculus, Transaction Management, Concurrency Control
  4. Paper-2 | Algorithms: Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Greedy Algorithms, Dynamic Programming, Minimum Spanning Trees, Shortest Path Algos
  5. Paper-2 | Computer Networks & Security: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware Basics, Network Access Technologies, Network Security
  6. Paper-2 | Digital Logic: Digital Systems & Boolean Basics, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits, Number System, Number Representation, Floating Point Rep
  7. Paper-2 | Operating System: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management
  8. Paper-2 | Theory of Computation: Introduction to TOC, Deterministic FA (DFA), Non-Deterministic FA, Regular Expressions, Grammar, Regular Language Properties, Moore & Mealy Machines, Pushdown Automata & CFG, Turing Machines
  9. Paper-2 | Computer Organization & Architecture: Basics of COA, Cache Memory Organization, Input Output Organisation, Pipelining, Instr Formats & Modes, Control Unit Design, Programming the Basic Computer
  10. Paper-2 | Compiler Design: Intro to Compilers, Lexical Analysis, Grammar & CFG, Syntax Analysis: Top-Down, Syntax Analysis: Bottom-Up, Semantic Analysis & SDT, Intermediate Code Gen, Code Optimization, Run Time Environment
  11. Paper-1 | General Awareness: Polity, Physics, Biology, Chemistry, Static General Knowledge, GK- Current Affairs, History, Geography, Indian Economy, Environment
  12. Paper-1 | Logical Reasoning: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Data Interpretation, Blood Relations, Syllogisms, Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Selection Decision Table (Decision Making), Clock, Calendar, Cubes & Dices, Directions (Direction Test), Analogy, Seating Arrangements, Analytical Reasoning (Counting Figures Reasoning)
  13. Paper-1 | Quantitative Aptitude: Ratio and Proportion (Ratios), Mixture and Alligation, Permutation and Combination, Number System, HCF LCM, Speed Time and Distance, Average, Age Problems, Percentage, Profit and Loss, Time and Work, Pipe and Cistern, Simple Interest and Compound Interest, Powers and Exponents (Surds and Indices), Mensuration and Geometry, Probability, Statistics, Arithmetic, Algebra
  14. Paper-1 | English: Vocabulary, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Sentence Construction, Cloze Test (Cloze Passage)
  15. Coal India Previous Year Paper:
  16. Engineering Mathematics: Set Theory, Relations, Functions, Graph Theory, Group Theory, Propositional and Predicate Logic, Linear Algebra, Calculus
  17. Coal India Mock Test:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

The video features an educational lecture by Sanchit Jain on digital logic design, focusing on constructing larger multiplexers (MUX) from smaller ones. The instructor demonstrates how to build larger MUX configurations using smaller, standard MUX units. The lesson begins with a visual demonstration of constructing a 16:1 MUX using 4:1 MUXes. It then transitions to numerical problems, calculating the exact number of 4:1 MUXes required to build a 128:1 MUX, and subsequently calculating the number of 8:1 MUXes needed for a 4096:1 MUX. The lecture concludes with a theoretical summary table that generalizes the method for any m-to-n MUX construction, providing formulas for the number of levels and the total count of MUXes required.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The instructor introduces the first problem written on the whiteboard: "Q 16 : 1 MUX using 4 : 1 MUX ?". He begins by drawing a large rectangle to represent the target 16:1 MUX. Inside, he sketches smaller rectangles to represent the 4:1 MUX components. He draws input lines on the left and connects them to the blocks. He writes the calculation "16/4 + 4/4" on the board, indicating the first step in determining the number of components needed. He circles the "4:1 MUX" text in the question to emphasize the building block.

  2. 2:00 – 5:00 02:00-05:00

    The topic shifts to a new numerical problem: "Q how many 4X1 Mux are required in order to construct 128X1?". The instructor performs a step-by-step division on the whiteboard. He writes "128/4" resulting in 32, then "32/4" resulting in 8, then "8/4" resulting in 2, and finally "2/4" resulting in 1. He sums these values to get a total of 43, writing "32 + 8 + 2 + 1 = 43 (4x1)". He then refines this calculation, writing "32 + 8 + 2 = 42 (4x1)" and "1 (2x1)" below it, suggesting a discussion on the final stage requiring a smaller MUX.

  3. 5:00 – 6:01 05:00-06:01

    The final problem asks: "Q how many 8X1 Mux are required in order to construct 4096X1?". The instructor repeats the division method: 4096/8 = 512, 512/8 = 64, 64/8 = 8, and 8/8 = 1. He writes the summation "512 + 64 + 8 + 1" and uses tally marks to visualize the counts. Finally, he displays a summary table on the screen. The table lists "Given: m X 1", "Target: n X 1", "No of levels(K) = log_m n", and "No of Mux at i^th level (x_i) = (n/m^i)". He points to the formula for "Total Mux required". A meme of a cat labeled "BORED" is visible on the right side.

The lecture follows a logical progression from concrete visualization to abstract calculation and finally to general theory. By starting with a 16:1 MUX, the instructor establishes the visual concept of cascading smaller units. He then reinforces this with the 128:1 example, forcing the student to perform the arithmetic of summing the geometric series of MUX counts. The 4096:1 example scales this up to show the method's applicability to larger systems. The concluding table serves as a cheat sheet, providing the mathematical formulas (log_m n and summation) that underpin the manual calculations performed earlier, ensuring students can solve any similar problem efficiently.

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