The following grammar is: S → Aa | bAc | Bc | bBa A → d B → d

2019

Answer: D. LR(1) but not LALR(1)

1. A.

   Not LR(1) but LALR(1)

2. B.

   Neither LR(1) nor LALR(1)

3. C.

   LR(1) and LALR(1)

4. D.

   LR(1) but not LALR(1)

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Correct answer: D