Practice Question-1

Duration: 4 min

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Inside: a video lesson and guided study material.

Module outline

  1. Section A | English: Vocabulary, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions), Preposition, Sentence Correction (Error Correction), Sentence Completion (Fill in the blanks), Articles, Sentence Re-arrangements (Para Jumbles) (Narrative Sequencing), Verbal Analogy (Word Based Analogy)
  2. Section A | Quant Aptitude: Ratio and Proportion (Ratios), Mixture and Alligation, Permutation and Combination, Number System, HCF LCM, Sequence and Series (Series), Speed Time and Distance, Arithmetic, Algebra, Powers and Exponents (Surds and Indices), Average, Age Problems, Percentage, Profit and Loss, Partnership, Time and Work, Simple Interest and Compound Interest, Mensuration and Geometry, Probability, Pipe and Cistern
  3. Section A | Reasoning: Series (Number and Letter Series) (Numerical Relations and Reasoning), Coding Decoding, Data Sufficiency, Calendar, Clock, Blood Relations, Directions (Direction Test), Seating Arrangements, Ranking, Order and Sequence, Puzzle Solving (Puzzles)
  4. Section B | C Programming: C Programming by Yash Sir, Coding Questions by Yash Sir
  5. Section B | Data Structures: Algorithm Analysis, Greedy Algorithms, Time Complexity Analysis, Sorting Algorithms, Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs
  6. Section B | OOP (C++): Object Oriented Programming (OOPS), Programming in C++
  7. Section B | OS: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management, Windows OS
  8. Section B | Networking: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics
  9. Section B | AI & Big Data Basics: AI & ML by Arun Sir, Big Data Systems
  10. Section C | Digital Electronics: Digital Systems & Boolean Basics, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits, Number System, Number Representation, Analog-Digital Conversion
  11. Section A, C | Comp. Fundamentals, COA: Basics of COA, Floating Point Rep, Cache Memory Organization, Input Output Organisation, Pipelining, Instr Formats & Modes, Control Unit Design, Register Transfer and Microoperations, Multiprocessors, Programming the Basic Computer
  12. MOCK TEST:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

The video presents a step-by-step solution to a problem in computer architecture concerning a micro-programmed control unit. The instructor begins by analyzing the requirements: the system must support 256 instructions, 16 flag conditions, and generate 48 control signals. The first part of the solution calculates the number of bits required for each control word. This is done by determining the number of bits needed for the instruction address (log2(256) = 8 bits), the flag conditions (log2(16) = 4 bits), and the control signals (48 bits). The total is the sum of these: 8 + 4 + 48 = 60 bits. The second part calculates the total control memory size in bytes. The instructor multiplies the number of instructions (256) by the number of bits per control word (60) to get the total number of bits (15,360). This is then converted to bytes by dividing by 8, resulting in 1,920 bytes. The entire process is demonstrated on a whiteboard with clear, handwritten calculations.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The video starts with the instructor presenting a problem about a micro-programmed control unit. The on-screen text states the system must support 256 instructions, 16 flag conditions, and generate 48 control signals. The instructor begins to break down the problem, writing '256 instruction' and '16 flag' on the whiteboard. He then calculates the number of bits required for the instruction address, writing 'log2(16)' and 'log2(16) = 4' to determine that 4 bits are needed for the flag conditions. He also writes '48 control signal' to account for the control signals. The instructor is seen writing 'log2(16)' and 'log2(16) = 4' on the whiteboard, indicating the calculation for the flag conditions.

  2. 2:00 – 3:56 02:00-03:56

    The instructor continues the calculation for the first part of the problem. He writes 'log2(256)' and calculates it as 8, determining that 8 bits are needed for the instruction address. He then adds the bits for the instruction address (8), flag conditions (4), and control signals (48), writing '8 + 4 + 48 = 60 bits' to find the total bits per control word. For the second part, he calculates the total control memory size. He multiplies the number of instructions (256) by the bits per control word (60), writing '256 x 60 = 15,360 bits'. He then converts this to bytes by dividing by 8, writing '15,360 / 8 = 1,920 bytes'. The final answer for the control memory size is clearly written as 1,920 bytes.

The video provides a clear, methodical walkthrough of calculating the control memory requirements for a micro-programmed control unit. It demonstrates the fundamental principle that the size of the control memory is determined by the number of instructions and the size of each control word. The control word size is the sum of the bits needed to address the instruction, the bits to represent the flag conditions, and the bits for the control signals. The solution is broken down into two logical steps: first, calculating the bits per control word, and second, calculating the total memory size by multiplying the number of instructions by the bits per word and converting to bytes. This approach effectively teaches the core concepts of control memory design in computer architecture.

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