Practice Question

Duration: 3 min

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Inside: a video lesson and guided study material.

Module outline

  1. English Communication: Communication Assessment, English Writing Ability, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions)
  2. Artificial Intelligence (AI Literacy): AI & ML by Arun Sir
  3. Programming, Logic & Problem Solving (Technical Assessment): Language Design, Pseudo Codes
  4. DSA (Technical Assessment): Introduction to DS, Array, Stack, Queue, Linked List
  5. Software Engineering (Technical Assessment): Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  6. OOPs (Technical Assessment): Object Oriented Programming (OOPS)
  7. DBMS (Technical Assessment): Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, Relational Calculus, Transaction Management, Concurrency Control, Database Recovery, ORDBMS, Database Security & Authorization, Query Processing & Optimization, Enhanced Data Models, Data Warehousing & Mining, Big Data Systems, NoSQL
  8. SQL (Technical Assessment): SQL
  9. Networking (Technical Assessment): Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Mobile Technology
  10. Modern Engg Awareness (Technical Assessment): Emerging Tech Trends, Cyber and Info Security
  11. Debugging Assessment: Coding Questions by Yash Sir, C Programming by Yash Sir, Programming in C++, Java
  12. Cognitive Assessment: Gamified / Game Based Aptitude, Seating Arrangements, Puzzle Solving (Puzzles), Data Arrangement, Blood Relations, Directions (Direction Test), Coding Decoding, Series (Number and Letter Series) (Numerical Relations and Reasoning), Logical Sequence Of Words, Ranking, Order and Sequence, Data Sufficiency, Inequality, Venn Diagram, Syllogisms, Cubes & Dices, Calendar, Clock, Analytical Reasoning (Counting Figures Reasoning), Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Selection Decision Table (Decision Making), Behavioral Assessment (Behavioral Competency Profiling) (Psychometric Test)
  13. HR Interview: MR & HR Interview Preparation
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This educational video demonstrates how to calculate the memory address of a specific element within a two-dimensional array using the Row Major Order storage scheme. The instructor presents a specific problem where the array A has non-standard indexing ranges: rows from 5 to 15 and columns from -8 to 8. The total dimensions are given as A[11][17]. The problem asks for the address of element A[8][5]. Essential parameters are provided: a Base Address of 800 and an element size of 4 memory cells. The lecture walks through the derivation of the address calculation formula and applies it to solve the numerical problem, highlighting the handling of negative lower bounds.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The session begins with the problem statement displayed on screen: Q A[5.....15, -8.....8] is A[11][17] and we are supposed to find A[8][5]. The instructor identifies the given values: Row Major Order, Base Address = 800, and element size w = 4. He writes the general formula for Row Major Order on the board: A[i, j] = B + w * [(i - li) (ul - ll + 1) + (j - lj)]. He explicitly defines the lower and upper limits for rows (li=5, ui=15) and columns (lj=-8, uj=8). He notes that the term (ul - ll + 1) represents the total number of columns, which is 17. He sets up the substitution for the target element A[8][5], identifying i=8 and j=5.

  2. 2:00 – 3:14 02:00-03:14

    The instructor performs the arithmetic substitution. He writes 800 + 4 * [(8 - 5) * 17 + (5 - (-8))]. He calculates the row difference (8 - 5) as 3. He calculates the column difference (5 - (-8)) as 13. He multiplies the row difference by the column count: 3 * 17 = 51. He adds the column difference to this product: 51 + 13 = 64. This sum represents the total number of elements skipped. He multiplies this by the element size: 4 * 64 = 256. Finally, he adds this offset to the base address: 800 + 256, resulting in the final address 1056.

The video provides a clear, step-by-step guide to memory address calculation for 2D arrays. It emphasizes the formula's structure, particularly how the row index is weighted by the total column count. The example with negative lower bounds serves as a practical test of understanding the (index - lower_limit) component of the formula. The final calculation confirms the address is 1056, reinforcing the method for handling non-zero-based indexing in programming and data structures.

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