Practice question

Duration: 2 min

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Inside: a video lesson and guided study material.

Module outline

  1. English Communication: Communication Assessment, English Writing Ability, Comprehension / Reading Comprehension / Unseen Passages (Critical Reasoning) (Paragraph Questions)
  2. Artificial Intelligence (AI Literacy): AI & ML by Arun Sir
  3. Programming, Logic & Problem Solving (Technical Assessment): Language Design, Pseudo Codes
  4. DSA (Technical Assessment): Introduction to DS, Array, Stack, Queue, Linked List
  5. Software Engineering (Technical Assessment): Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  6. OOPs (Technical Assessment): Object Oriented Programming (OOPS)
  7. DBMS (Technical Assessment): Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, Relational Calculus, Transaction Management, Concurrency Control, Database Recovery, ORDBMS, Database Security & Authorization, Query Processing & Optimization, Enhanced Data Models, Data Warehousing & Mining, Big Data Systems, NoSQL
  8. SQL (Technical Assessment): SQL
  9. Networking (Technical Assessment): Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer, Hardware basics, Network Security, Mobile Technology
  10. Modern Engg Awareness (Technical Assessment): Emerging Tech Trends, Cyber and Info Security
  11. Debugging Assessment: Coding Questions by Yash Sir, C Programming by Yash Sir, Programming in C++, Java
  12. Cognitive Assessment: Gamified / Game Based Aptitude, Seating Arrangements, Puzzle Solving (Puzzles), Data Arrangement, Blood Relations, Directions (Direction Test), Coding Decoding, Series (Number and Letter Series) (Numerical Relations and Reasoning), Logical Sequence Of Words, Ranking, Order and Sequence, Data Sufficiency, Inequality, Venn Diagram, Syllogisms, Cubes & Dices, Calendar, Clock, Analytical Reasoning (Counting Figures Reasoning), Deductive and Inductive Reasoning (Logical Deduction and Induction) (Prepositional Reasoning), Non Verbal Reasoning (Spatial Aptitude) (Spatial Reasoning) (Visual Reasoning), Selection Decision Table (Decision Making), Behavioral Assessment (Behavioral Competency Profiling) (Psychometric Test)
  13. HR Interview: MR & HR Interview Preparation
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This short practice-question video demonstrates how to compute the memory address of a specific element in a one-dimensional array. The on-screen question states that the base address of the first element is 250, each element occupies 3 bytes, and asks for the address of the fifth element in array a[10]. The instructor first identifies the given values, writing B = 250 and w = 3B in red handwriting. A diagram of the array is drawn as a rectangle with indices 0 through 9 written above it, emphasizing that the fifth element corresponds to index 4 because indexing starts at zero. The solution is then computed manually as 250 + (4 × 3) = 262. A formal array addressing formula, a[k] = B + w * (k - Lb), is also shown and applied with k = 4, B = 250, w = 3, and Lb = 0 to verify the same result. The final answer, 262 bytes, is underlined in red.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The slide displays the orange question: "Let the base address of the first element of the array is 250 and each element of the array occupies 3 bytes in the memory, then address of the fifth element of a one-dimensional array a[10]?" Red handwriting appears showing "B = 250" and "w = 3B", with a red underline under "first element". An empty red rectangle is drawn, then index numbers "0 1 2 3 4 5 6 7 8 9" are written above it to show the fifth element is at index 4. The working expands to "=250 + 4*3B", then "250 + 12", and finally "= 262B" underlined in red. A formal formula, a[k] = B + w * (k - Lb), is shown and applied with k=4, B=250, w=3 to yield 262.

The central concept is array element address calculation using the formula a[k] = B + w * (k - Lb), where B is the base address, w is the word size in bytes, k is the target index, and Lb is the lower bound (starting index). The key teaching point is that "fifth element" means index 4 in a zero-based array, not index 5. The instructor demonstrates both a manual offset calculation (base + index × word size) and the formal formula, arriving at 262 bytes. This reinforces that address computation depends on the index offset from the lower bound multiplied by element size, added to the base address.

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