Short Trick to Divide a Given Number X in ratio of M N

Duration: 16 min

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Module outline

  1. About the course: About the Course
  2. Mathematical Aptitude / गणितीय अभिक्षमता: Number System / संख्या पद्धति, HCF and LCM / महत्तम समापवर्तक और लघुत्तम समापवर्त्य, Divisibility Rules / विभाज्यता के नियम, Percentage / प्रतिशत, Ratio and Proportion / अनुपात और समानुपात, Average / औसत, Profit, Loss and Discount / लाभ, हानि और बट्टा, Time and Work / समय और कार्य, Solid Mensuration / घन क्षेत्रमिति, Simple and Compound Interest / साधारण और चक्रवृद्धि ब्याज, Time, Speed and Distance / समय, चाल और दूरी, Age Problems / आयु संबंधी प्रश्न, Mixture and Alligation / मिश्रण और एलिगेशन, Algebra / बीजगणित, Simplification, Indices and Surds / सरलीकरण, घातांक और करणी, Pipe and Cistern / नल और टंकी, Trigonometry / त्रिकोणमिति, Statistics / सांख्यिकी, Data Interpretation / आँकड़ा निर्वचन, Arithmetic / अंकगणित, Sets, Relations, Functions and Discrete Mathematics / समुच्चय, संबंध, फलन और विविक्त गणित, Number Systems and Number Theory / संख्या पद्धति और संख्या सिद्धांत, Coordinate Geometry, Vectors and 3D Geometry / निर्देशांक ज्यामिति, सदिश और त्रिविमीय ज्यामिति, Polynomials, Equations and Complex Numbers / बहुपद, समीकरण और सम्मिश्र संख्याएँ
  3. Logical Reasoning / तार्किक तर्कशक्ति: Series / श्रेणी, Coding-Decoding / कूट लेखन एवं कूट वाचन, Analogy and Classification / सादृश्यता एवं वर्गीकरण, Blood Relations / रक्त संबंध, Direction and Distance / दिशा एवं दूरी, Order and Ranking / क्रम एवं रैंकिंग, Non-Verbal Reasoning / अशाब्दिक तर्क, Seating Arrangement and Puzzles / बैठक व्यवस्था एवं पहेलियाँ, Syllogisms / न्यायवाक्य, Venn Diagrams, Syllogism and Inequalities / वेन आरेख, न्याय वाक्य एवं असमानता, Mathematical Operations and Missing Numbers / गणितीय संक्रियाएँ एवं लुप्त संख्या, Alphabet and Number Test / वर्णमाला एवं संख्या परीक्षण, Statement-Based Reasoning / कथन आधारित तार्किक विवेचन, Analytical Reasoning (Counting Figures Reasoning) / विश्लेषणात्मक तर्क (आकृति गणना तर्क), Cubes, Dice and Figure Counting / घन, पासा एवं आकृतियों की गिनती, Calendar and Clock / कैलेंडर एवं घड़ी, Clock / घड़ी
  4. General Knowledge / सामान्य ज्ञान: Scientific Achievements and Research / वैज्ञानिक उपलब्धियाँ और अनुसंधान, Chemistry / रसायन विज्ञान, Biology / जीव विज्ञान, History / इतिहास, Geography / भूगोल, Polity / राजव्यवस्था, Indian Economy / भारतीय अर्थव्यवस्था, Current Affairs / समसामयिकी, Static General Knowledge / स्थैतिक सामान्य ज्ञान, State-Specific General Knowledge / राज्य विशेष सामान्य ज्ञान
  5. Art of Teaching / शिक्षण कला: Teaching-Learning Process and Classroom Management / शिक्षण-अधिगम प्रक्रिया एवं कक्षा प्रबंधन, Learners & Learning Process / अधिगमकर्ता और अधिगम प्रक्रिया, Factors Affecting Teaching / शिक्षण को प्रभावित करने वाले कारक, Teaching Methods and Approaches / शिक्षण विधियाँ एवं उपागम, Microteaching and Classroom Communication / सूक्ष्म शिक्षण एवं कक्षा संप्रेषण, Teaching Aids and Educational Technology / शिक्षण सहायक सामग्री एवं शैक्षिक तकनीकी, Assessment and Evaluation / आकलन एवं मूल्यांकन, Teacher: Qualities, Professional Ethics and Development / शिक्षक: गुण, व्यावसायिक नैतिकता एवं विकास, Educational Policies, Acts and Administration / शैक्षिक नीतियाँ, अधिनियम एवं प्रशासन, Curriculum, Arts and Co-curricular Areas / पाठ्यचर्या, कला एवं सह-शैक्षिक क्षेत्र, Guidance and Counselling / निर्देशन एवं परामर्श, Education of Children with Disabilities / दिव्यांग बच्चों की शिक्षा, Micro-Teaching & Teaching Skills / सूक्ष्म शिक्षण और शिक्षण कौशल, Lesson Planning / पाठ योजना
  6. Environmental Science / पर्यावरण विज्ञान: Environment / पर्यावरण
  7. Unit 1 | Digital Electronics: Digital Systems & Boolean Basics, Logic Gates & Hardware, Boolean Expression, Boolean Minimization, Combinational Circuit, Sequential Circuits, Number System, Number Representation
  8. Unit 2 | COA: Basics of COA, Floating Point Rep, Cache Memory Organization, Input Output Organisation, Instr Formats & Modes, Control Unit Design, Register Transfer and Microoperations, Programming the Basic Computer
  9. Unit 3 | C Programming: C Fundamentals, Control Flow, Functions, Arrays & Pointers, Storage Classes, Structures & Enums, DMA, Macros, Scoping & File Handling
  10. Unit 3 | Data Structures: Introduction to DS, Array, Stack, Queue, Linked List, Tree, Graphs, Hashing
  11. Unit 4 | Algorithms: Algorithm Analysis, Time Complexity Analysis, Sorting Algorithms, Dynamic Programming, Minimum Spanning Trees, Shortest Path Algos, Advanced Algorithms
  12. Unit 5 | Operating System: Introduction to OS, Process Management, CPU Scheduling, Process Synchronization, Threads & Process Creation, Deadlock, Memory Management, Virtual Memory, Disc Scheduling, File Management
  13. Unit 6 | Database Management System: Basics of DBMS, ER Diagram, Relational Model & Functional Dependencies, Keys & Integrity Constraints, Normalization (1NF - BCNF), Decomposition Properties & 4NF, File Organization & Indexing, Relational Algebra, SQL, Transaction Management, Concurrency Control
  14. Unit 7 | Computer Networks: Introduction to CN, Data Communication, DLL: Access Control, DLL: Flow Control, DLL: Error Control, DLL: Framing, Data Link Layer - Ethernet, Net Layer: IPv4 & Proto, Net Layer: IP Addressing, Net Layer:Routing Protocol, Transport Layer Services, TL: Congestion & UDP, Application Layer
  15. Unit 8 | Software Engineering: Fundamentals of Software Engineering, Software Requirements and Quality Assurance, Software Design, Estimation and Metrics, Software Testing, Software Maintenance and Configuration Management
  16. Unit 9 | Object Oriented Programming: OOPS with C++
  17. Unit 10 | Web Development: HTML Basics, CSS, JavaScript-Basics, XML, Node.js, Git & Github, PHP
  18. Unit 11 | Theory Of Computation: Introduction to TOC, Deterministic FA (DFA), Non-Deterministic FA, Regular Expressions, Grammar, Regular Language Properties, Moore & Mealy Machines, Pushdown Automata & CFG, Turing Machines
  19. Unit 12 | IoT: Emerging Tech Trends, Cloud Computing, Computer Networks, Internet of Things
  20. Unit 13 | Artificial Intelligence: Approaches to AI, Search Algorithms, Game Playing, Knowledge Representation, Natural Language Processing, Artificial Neural Networks, Genetic Algorithms
  21. Unit 14 | E-Commerce: Electronic Data Interchange and E-Commerce, Role of Internet and Web Services, Security in Mobile and Wireless Computing, Physical Security and Cryptography Basics, Cyber Safety and Security
  22. Unit 15 | Multimedia: Multimedia
  23. Unit 16 | Python: Introduction to Python, Tokens, Variables, Data Types, I/O, Operators & Expressions, Control Flow & Looping, Collections & Strings, Functions & Modules, File Handling & Data Analysis, DSA using Python
  24. Full Length Mock Tests — General Paper:
  25. Full Length Mock Tests — Computer Science (Paper II):
  26. Full Length Mock Test – General + Computer Science:
AI summary & chapters

AI Summary

An AI-generated summary of this video lecture.

This lecture teaches a shortcut for dividing a given number x in the ratio m:n by first finding the value of one part and then multiplying it by each ratio term. The instructor opens with a definition of ratio as the comparison of two quantities, noting that it can be written in colon, word, or fraction form. The main method is introduced as “Dividing a given number 'x' in the ratio 'm:n'.” A story-based example uses Suresh and Mahesh, with a 153 lakh property to be divided in the ratio 4:5. The total number of parts is found as 4 + 5 = 9, so one part equals 153/9 = 17 lakh. Suresh’s share is then calculated as 4 × 17 = 68 lakh, and Mahesh’s share as 5 × 17 = 85 lakh. The instructor verifies the answer by adding the two shares back to 153 lakh. A second example involves Jethalal, Sunderlal, and Taarak Bhai sharing a profit of Rs. 10,85,000 in the efficiency ratio 7:11:13. The total number of parts is 7 + 11 + 13 = 31, so one part equals 10,85,000/31 = Rs. 35,000. Sunderlal’s share is highlighted as 11 × 35,000 = Rs. 3,85,000. A third example introduces chained ratios: Rs. 200 is divided among Neha, Tony, and Sonu such that N:T = 2:3 and T:S = 3:5. The instructor combines these into a single ratio N:T:S = 2:3:5, giving 10 parts equal to 200. One part is therefore 20, so Neha’s share is 2 × 20 = 40 and Tony’s share is 3 × 20 = 60. The final example extends the chained-ratio method to four people: Rs. 5000 is divided among Guddu, Munna, JP Yadav, and Kaleen Bhaiya with ratios G:M = 1:2, M:J = 2:3, and J:K = 3:4. These are combined into G:M:J:K = 1:2:3:4, giving 10 parts equal to 5000. One part is 500, so Munna’s share is 2 × 500 = Rs. 1000, which is circled as the answer. The lesson ends with a “THANKS FOR WATCHING” screen.

Chapters

  1. 0:00 – 2:00 00:00-02:00

    The video opens with a slide titled “RATIO & PROPORTION” that defines ratio as “a comparison of 2 quantities” and states it can be written in colon, word, or fraction form. The instructor then introduces the specific topic: “Dividing a given number 'x' in the ratio 'm:n'.” A “Story Time” segment begins with an illustration of three men, two of whom are labeled “Suresh” and “Mahesh,” followed by a house illustration labeled “Father.” This sets up the contextual word problem that will be solved using the ratio-division shortcut.

  2. 2:00 – 5:00 02:00-05:00

    The story problem is formalized as “153 lakh property into two parts in the ratio 4:5,” with Suresh associated with 4 and Mahesh with 5. The instructor writes “153 -> 9 parts” and “9 parts -> 153 lakh,” then calculates one part as 153/9 = 17 lakh. The individual shares are found by multiplying: “Suresh -> 4 x 17 lakh = 68 lakh” and “Mahesh -> 5 x 17 = 85 lakh.” A verification step adds the two shares back to confirm they total 153 lakh, reinforcing that the parts must sum to the original amount.

  3. 5:00 – 10:00 05:00-10:00

    A partnership problem is presented in an orange panel: Jethalal, Sunderlal, and Taarak Bhai have an efficiency ratio of 7:11:13 and a total profit of Rs. 10,85,000. The instructor labels the ratio as “Bhag ← efficiency ratio” and computes the total parts: 7 + 11 + 13 = 31. One part is then found as 10,85,000/31 = Rs. 35,000. Each partner’s share is obtained by multiplying their ratio term by 35,000; Sunderlal’s share of 11 × 35,000 = Rs. 3,85,000 is circled as the answer. This example demonstrates applying the same one-part method to a three-way division.

  4. 10:00 – 15:00 10:00-15:00

    The lesson moves to chained ratios. First, Rs. 200 is divided among Neha, Tony, and Sonu with N:T = 2:3 and T:S = 3:5. The instructor writes the fractions N/T = 2/3 and T/S = 3/5, then combines them into the single ratio N:T:S = 2:3:5. Since 2 + 3 + 5 = 10 parts equal 200, one part is 20. Neha’s share is calculated as 2 × 20 = 40 and Tony’s as 3 × 20 = 60. A second chained-ratio problem then introduces Rs. 5000 divided among Guddu, Munna, JP Yadav, and Kaleen Bhaiya with G:M = 1:2, M:J = 2:3, and J:K = 3:4.

  5. 15:00 – 15:30 15:00-15:30

    The final chained-ratio problem is completed. The ratios G:M = 1:2, M:J = 2:3, and J:K = 3:4 are combined into G:M:J:K = 1:2:3:4, giving 1 + 2 + 3 + 4 = 10 parts equal to 5000. One part is therefore 500, and the four shares are labeled 500, 1000, 1500, and 2000. Munna’s share of (2/10) × 5000 = Rs. 1000 is circled as the answer, and the video ends with a “THANKS FOR WATCHING” screen.

The central idea of the lecture is a consistent shortcut for dividing a number in a given ratio: sum the ratio terms to get the total number of parts, divide the original amount by that sum to find the value of one part, and then multiply each ratio term by this unit value to obtain individual shares. This method is first demonstrated with a simple two-way division (153 lakh in the ratio 4:5), where one part equals 17 lakh and the shares are 68 and 85 lakh. It is then extended to a three-way partnership division (Rs. 10,85,000 in the ratio 7:11:13), where one part equals Rs. 35,000 and Sunderlal’s share is Rs. 3,85,000. The most important conceptual extension involves chained ratios, where separate pairwise ratios must first be combined into a single multi-term ratio before applying the one-part method. In the Neha-Tony-Sonu example, N:T = 2:3 and T:S = 3:5 are combined into N:T:S = 2:3:5 because the common term Tony is already consistent (3 in both ratios). In the final four-person example, G:M = 1:2, M:J = 2:3, and J:K = 3:4 are combined into G:M:J:K = 1:2:3:4, again because the overlapping terms match. The verification step in the first example—adding the calculated shares back to the original total—is a useful habit that confirms correctness. The lecture uses story-based framing and character names to make the abstract ratio concept concrete, but the underlying arithmetic is identical across all examples: total parts → value of one part → individual shares.

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