Let z be a complex number. Then the series ∑ₙ₌₀^∞ z²ⁿ/(2n)!
GATE · 2020 · XE · XE-A — Engineering Mathematics
Let z be a complex number. Then the series ∑ₙ₌₀^∞ z²ⁿ/(2n)!
- A.
converges for all z.
- B.
converges for |z| ≤ 1 and diverges for |z| > 1.
- C.
converges for z = 0 and diverges for any z ≠ 0.
- D.
converges for |z| < 1 and diverges for |z| ≥ 1.
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