Newton-Raphson iteration formula for finding ∛c, where c > 0, is:

GATE · 1996 · CS · Question 2 subparts

1. A.

   xₙ₊₁ = (2xₙ³ + ∛c) / (3xₙ²)

2. B.

   xₙ₊₁ = (2xₙ³ - ∛c) / (3xₙ²)

3. C.

   xₙ₊₁ = (2xₙ³ + c) / (3xₙ²)

4. D.

   xₙ₊₁ = (2xₙ³ - c) / (3xₙ²)

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