What will be the output of the following pseudo code? Integer a, b, c, d, e…

Tracing a while loop means executing its body once per pass, in the exact order written, updating each variable as instructed, until the guard condition (c > 0) turns false. Every variable used inside the body -- including an accumulator like e -- must start from an initial value before the loop begins, and that value carries forward, changing only where the body explicitly updates it.

Initial values: a = 50, b = 3, c = 3, e = 0. Since a and b never change inside the loop, d = a mod b is the same in every pass.

1. Iteration 1: d = 50 mod 3 = 2; e = 0 + 2 + 50 = 52; c becomes 2.

2. Iteration 2: d = 50 mod 3 = 2; e = 52 + 2 + 50 = 104; c becomes 1.

3. Iteration 3: d = 50 mod 3 = 2; e = 104 + 2 + 50 = 156; c becomes 0.

Cross-check: because d stays fixed at 2 across all three passes, each pass adds the same (d + a) = 52 to e, so after n passes e = n x 52. The guard c > 0 lets the loop run exactly 3 times (c: 3 to 2 to 1 to 0), so e = 3 x 52 = 156, confirming the step-by-step trace.

The loop then exits (c = 0) and Print e outputs 156.